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valentina_108 [34]
2 years ago
11

Each side a square calendar is 7 inches long. what is the calendar's area

Mathematics
1 answer:
Rudik [331]2 years ago
4 0

Answer:

49 square inches

Step-by-step explanation:

Length x width =area

since it is a square, all sides have a length of 7 inches

7x7=49 inches ^2

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How to compare 2 5/9 and 21/3
max2010maxim [7]

Answer:

2 5/9 is less than 21/3;  2 5/9 < 21/3

Step-by-step explanation:

<u>Step 1:  Convert 2 5/9 into an improper fraction</u>

2 5/9 = 2 * 9/9 + 5/9 = 18/9 + 5/9 = 23/9

<u>Step 2:  Convert 21/3 so the denominator is 9</u>

21*3 / 3*3 = 63/9

<u>Step 3:  Compare</u>

<em>23/9 < 63/9</em>

<em />

Answer:  2 5/9 is less than 21/3;  2 5/9 < 21/3

5 0
3 years ago
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Divide x4+2x2−24<br> by x+2
Ipatiy [6.2K]

\begin{array}{c|c}_{-}\ x^4+2x^2-24 &\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\! \underline{  x+2  } \\ \!\!\!\!\!\!\!\!\!\!\! \underline{x^4+2x^3}& x^3-2x^2+4x-8  \\{ \big{_{-}}}-2x^3-24& \\\underline{-2x^3-4x^2}& \\  _{-} \ 4x^2-24 & \\ \underline{4x^2+8x}&   \\  _{-}-8x-24& \\ \underline{-8x-16} & \\ -8 &\end {array }

\displaystyle \frac{x^4+2x^2-24}{x+2} =x^3-2x^2+4x-8 -\frac{8}{x+2}

7 0
2 years ago
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√√√√√√√√√√√√√√√√√√√√√√
iogann1982 [59]

Answer:

0

Step-by-step explanation:

This question is impossible to answer

3 0
2 years ago
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The estimated product of two numbers that are not multiples of 10 is 2800. what is the question?
Nitella [24]
You need to find the 2 numbers that will estimate to the nearest hundred.
here is your answer 13 x 213
4 0
3 years ago
Find the difference when the polynomial -5x^2+3x+8 is subtracted from the polynomial 2x^2+4x+1.
geniusboy [140]

The difference is 7x^{2}  + 1x-7.

Step-by-step explanation:

Step 1:

The polynomial -5x^{2}+3x+8 is subtracted from the polynomial 2x^{2} + 4x +1.

If we write this as an equation, we get

(2x^{2} + 4x +1) -(-5x^{2}+3x+8).

To subtract the polynomials, we group up the terms based on their variables.

In this subtraction, there are two variables i.e. x^{2} and x and there is one constant term.

Step 2:

The subtraction of the x^{2} variables; 2x^{2}  -(-5x^{2} )  = 2x^{2} +5x^{2} = 7x^{2}.

The subtraction of the x variables; 4x - (3x) = 1x.

The subtraction of the constants; 1-(8) = -7.

So (2x^{2} + 4x +1) -(-5x^{2}+3x+8) = 7x^{2}  + 1x-7.

4 0
2 years ago
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