3 years ago

I need help with this question it's really hardd

Mathematics

1 answer:

Vsevolod [243]3 years ago

7 0

1st one on second row I think

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Which inequality has the solution shown below?

olasank [31]

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2 years ago

If a,b,c,d, and e are non negative such that x^6-289x^4-x^2+289=(x-a)(x+b)(x_c)(x+d)(x^2+ex+1), what is the value of a+b+c+d+e?

Irina18 [472]

Answer:

Step-by-step explanation:

Hello,

If $X=x^2$ it becomes

$X^3-289X^2-X+289=(X^2-1)(X-289)$

and $289=17^2$

$X^2-1=(X-1)(X+1)=(x^2-1)(x^2+1)=(x+1)(x-1)(x^2+1) \\\\x^2-289=x^2-17^2=(x-17)(x+17)$

So,

$x^6-289x^4-x^2+289=(x^2-1)(x^2+1)(x^2-289)=(x-1)(x+1)(x+17)(x-17)(x^2+1)$

a = 1

b = 1

c = 17

d = 17

e = 0

Then a + b + c + d + e = 36

Thanks

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2 years ago

The expression 4x/5-2x/3 is equivalent to what?

Vinvika [58]

Answer:

(2 x)/15

Step-by-step explanation:

Simplify the following:

(4 x)/5 - (2 x)/3

Put each term in (4 x)/5 - (2 x)/3 over the common denominator 15: (4 x)/5 - (2 x)/3 = (12 x)/15 - (10 x)/15:

(12 x)/15 - (10 x)/15

(12 x)/15 - (10 x)/15 = (12 x - 10 x)/15:

(12 x - 10 x)/15

12 x - 10 x = 2 x:

Answer: (2 x)/15

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2 years ago

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Step-by-step explanation:

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2 years ago

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Which is equivalent to 80^1/4x ?

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Answer: This expression is equivalent to 3^x

Step-by-step explanation: In this question the important concept is to write 80 in exponential form and multiply the exponents.

=80^1/4x

=(3^4)^1/4x

=3^x

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2 years ago