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Nutka1998 [239]
3 years ago
7

Elise won 40 lollipops and the school fair. she gave 2 to every student in her math class and has at least 7 left. what is the m

aximum number of students in her class?
Mathematics
2 answers:
geniusboy [140]3 years ago
8 0
40-7= 33
33/2= 16.5
The maximum would be 17 students
Alchen [17]3 years ago
3 0
40 lollipops minus at least 7 = 33 lollipops33 lollipops divided by 2 = 16.5 classmatesElisa has 16 classmates who were given 2 lollipops, so she has 8 leftover of the 40 she won playing basketball.

Hope this helps  :)
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Which is traveling faster, a car whose velocity vector is 201 + 25), or a car whose velocity vector is 30i, assuming that the un
ioda

Answer with explanation:

For any object having the velocity vector as

\overrightarrow{v}=v_x\widehat{i}+v_y\widehat{j}+v_z\widehat{k}

the magnitude of velocity is given by

|v|=\sqrt{v_x^2+v_y^2+v_z^2}

For car 1 the velocity vector is

\overrightarrow{v}_1=20\widehat{i}+25\widehat{j}

Therefore

|v_1|=\sqrt{20^2+25^2}\\\\\therefore v_1=32.0156units

Similarly for car 2 we have

\overrightarrow{v}_2=30\widehat{i}

Therefore

|v_2|=\sqrt{30^2}\\\\\therefore v_2=30.0units

Comparing both the values we find that car 1 has the greater speed.

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3 years ago
Solve 3(4y + 6) greater equal to -2(3-6y) show work pls
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Answer:

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Step-by-step explanation:

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Which is the correct classification of sqrt 32
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Answer:

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Researchers are interested if a school breakfast program leads to taller children. Assume that the population of all 5 year-old
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Answer:

39-1.96\frac{1}{\sqrt{25}}=38.608    

39+1.96\frac{1}{\sqrt{25}}=39.392    

So on this case the 95% confidence interval would be given by (38.608;39.392)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=39 represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=1 represent the population standard deviation

n=25 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

The margin of error is given by:

ME= z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

And replacing we got:

ME= 1.96 *\frac{1}{\sqrt{25}}= 0.392

Now we have everything in order to replace into formula (1):

39-1.96\frac{1}{\sqrt{25}}=38.608    

39+1.96\frac{1}{\sqrt{25}}=39.392    

So on this case the 95% confidence interval would be given by (38.608;39.392)    

7 0
3 years ago
3. For the equation-4y = &amp;r, what is the constant of variation? (1 point)<br> ООО<br> 02
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Answer:

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4).

y \alpha x \\ y = kx \\ where \: k \: is \: the \: constant \: of \: proportionality \\ when \: y = 24 \: and \: x = 8 \\ substitute \: in \: y = kx \\ 24 = 8k \\ k =  \frac{24}{8}  \\ k = 3 \\ value \: of \: constant = 3

If it was by 10, k = 3 by 10

k = 30

5).

general \: equation \: of \: line  \\ y = mx + c \\ but \: m =  \frac{2}{3}  \: and \: c = 9 \\ substitute \: for \: m \: and \: c \: in \: y = mx + c \\ y =  \frac{2}{3} x + 9 \\ alternatively \\ 3y = 2x + 27

7 0
3 years ago
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