3 years ago

When you multiply or divide an inequality by a negative number, keep the inequality symbol the same. TrueFalse

Mathematics

1 answer:

sweet [91]3 years ago

8 0

Answer is to the question is false

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Really need helpppp?!

user100 [1]

Answer:

6.43

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Step-by-step explanation:

length of side x will be

Tan tita = opp/adjacent

tan65 = x/3

tan 65 is 2.14

so...you are left with 2.14=x/3

by cross multiplying

x= 2.14 × 3

= 6.43

5 0

2 years ago

Ɪ ᴅᴏɴ'ᴛ ɢᴇᴛ ᴛʜɪs ᴄᴀɴ sᴏᴍᴇʙᴏᴅʏ ʜᴇʟᴘ ᴍᴇ ᴏɴ ᴛʜɪs ᴘʀᴏʙʟᴇᴍ ʀᴇᴀʟʟʏ ǫᴜɪᴄᴋ

Paraphin [41]

The answer would be reading

7 0

2 years ago

Read 2 more answers

kaye has $2.80 in nickels and dimes. she has three timesas many dimes as nickels. how many nickels and how many dimes does she h

Vitek1552 [10]

8 nickels, because 8 (nickels) × 5 (worth) = 40
24 dimes, because 8 × 3 = 24 24 × 10 = 240
240 + 40 = 280

4 0

3 years ago

Simplify the expression. 8x^-10 y^'6 -2x^2y^-8 Write your answer without negative exponents.

sergij07 [2.7K]

Answer:

$8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^{14} - 2x^{12}}{x^{10}y^8}$

Step-by-step explanation:

Given

$8x^{-10}y^6 - 2x^2y^{-8}$

Required

Simplify

Rewrite as:

$8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^6}{x^{10}} - \frac{2x^2}{y^8}$

Take LCM

$8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^6*y^8 - 2x^2 * x^{10}}{x^{10}y^8}$

Apply law of indices

$8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^{14} - 2x^{12}}{x^{10}y^8}$

8 0

2 years ago

HELP PLEASE !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

aleksandrvk [35]

50km to 80km is 30km

10c to -80c is -90c

and since it linear (Which means the change is constant or the same)

every 10 km show a -30c decrease

60 km is -20c

70km is -50c

answer is c

5 0

2 years ago