which of the following is true? a)speed is velocity w a vector b)speed is a scalar w direction c)speed is velocity w direction d
1 answer:
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Answer:
36,67 degrees Celsius
Explanation:
The simplest way to approach this problem, given the information provided, is to simply start with the speed difference.
Goal: 353 m/s
Start: 343 m/s (at 20 degrees Celsius).
Difference: 10 m/s
Variation rate: 0.60 m/s/d (d = degree)
So, 16,67 degrees more than the starting point.
The temperature will then be 36.67 degrees Celsius, when the sound travels at the speed of 353 m/s.
Answer:
The total pressure of the solution is 598.66 torr
while the vapor pressure of the components is vapor pressure of benzene is =502 torr and that of toluene = 96.6 tor
Explanation:
To solve this question, we need to look at the known variables, the unknown variables, and then we select the appropriate relations between the known variables and the unknown
Here we have the temperature of the gases t = 80°C
the pressures of benzene = 753 torr
the pressures of toluene = 290 torr
mole fraction of benzene in solution = 2/3
mole fraction of toluene in solution = 1/3
the unknown variables = composition of the solution and the total pressure of the solution
From here given the known variables and the required variables, the appropriate relation bstween the known and unknown variables is Route's Law
Raoult's relates the vapor pressure of a mixture of gases to the mole fraction of solute gases introduced in the gas solution. Raoult's Law is expressed by the formula: Psolution = Χsolvent1×Psolvent1 + Χsolvent2×Psolvent2+ ... .
where. Psolution = vapor pressure of the solution and
Χsolvent1 = mole fraction of solvent 1
Psolvent1 = vapor pressure of solvent1
Thus we have by Raoult's Law
=
×
+
×
which is =2/3×753 + 1/3×290 = 502 + 96.6 = 598.66 torr
and composition vapor pressure of benzene is 502 torr
while the composition vapor pressure of toluene is 96.6 torr
Answer:
λ = 396.7 nm
Explanation:
For this exercise we use the diffraction ratio of a grating
d sin θ = m λ
in general the networks works in the first order m = 1
we can use trigonometry, remembering that in diffraction experiments the angles are small
tan θ = y / L
tan θ = = sin θ
sin θ = y / L
we substitute
= m λ
with the initial data we look for the distance between the lines
d =
d = 1 656 10⁻⁹ 1.00 / 0.600
d = 1.09 10⁻⁶ m
for the unknown lamp we look for the wavelength
λ = d y / L m
λ = 1.09 10⁻⁶ 0.364 / 1.00 1
λ = 3.9676 10⁻⁷ m
λ = 3.967 10⁻⁷ m
we reduce nm
λ = 396.7 nm