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antoniya [11.8K]
3 years ago
9

What is kinematics..???​

Physics
1 answer:
swat323 years ago
7 0

Answer:

Kinematics is the study of motion, without any reference to the forces that cause the motion. It basically means studying how things are moving, not why they're moving. It includes concepts such as distance or displacement, speed or velocity, and acceleration, and it looks at how those values vary over time.

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an object 50 cm high is placed 1 m in front of a converging lens whose focal length is 1.5 m. determine the image height (in cm)
Juli2301 [7.4K]

Given :

An object 50 cm high is placed 1 m in front of a converging lens whose focal length is 1.5 m.

To Find :

the image height (in cm).

Solution :

By lens formula :

\dfrac{1}{v} - \dfrac{1}{u} = \dfrac{1}{f}

Here, u = - 100 cm

f =  150 cm

\dfrac{1}{v} - \dfrac{1}{-100} = \dfrac{1}{150}\\\\v = - 300 \ cm

Now, magnification is given by :

m = \dfrac{v}{u} = \dfrac{h_i}{h_o}\\\\h_i = \dfrac{300}{100}\times 1\\\\h_i = 3 \ m

Therefore, the image height is 3 m or 300 cm.

5 0
3 years ago
As shown in the video, earth has two tidal bulges at all times. approximately where are these bulges located?
Pepsi [2]
Tidal bulges are always on the opposite side of the Earth.
They are created because of the gravitational influence of the Moon on Earth and inertial's counter balance.

The side of the Earth that is facing the Moon is the closest to the Moon, and the gravitational force is the strongest when the distance is the smallest.  

As the Moon is trying to draw the water towards itself, the inertia tries to keep the water at its place. On the opposite side of the Earth, "behind the Moon",  the gravitational force of the Moon is the weakest, so inertia is the strongest. That's why tidal bulges are at the opposite side. 
4 0
4 years ago
A railroad car of mass M moving at a speed v1 collides and couples with two coupled railroad cars, each of the same mass M and m
Tatiana [17]

Answer:

Explanation:

Given

mass of each railroad is M

first railroad is moving with velocity v_1 and other two's with v_2

conserving Momentum

Mv_1+2Mv_2=3M v_f

where v_f is the final velocity of combined system

v_f=\frac{v_1+2v_2}{3}

(b)Initial Kinetic Energy

=\frac{1}{2}Mv_1^2+\frac{1}{2}2Mv_2^2

=\frac{1}{2}Mv_1^2+Mv_2^2

Final Kinetic Energy

=\frac{1}{2}3Mv_f^2=\frac{1}{6}M(v_1^2+4v_2^{2}+4v_{1}v_2)

Loss in Kinetic Energy

=\frac{1}{2}Mv_1^2+Mv_2^2-\frac{1}{6}M(v_1^2+4v_2^{2}+4v_{1}v_2)

=M(v_1-v_2^2)^2

7 0
4 years ago
An object is lifted at constant speed a distance h above the surface of the Earth in a time t. The total potential energy gain o
Romashka-Z-Leto [24]
B.the objects total weight
6 0
3 years ago
Usually the force of gravity on electrons is neglected. To see why, we can compare the force of the Earth’s gravity on an electr
miv72 [106K]

Answer:

6.4\cdot 10^{-15} N

Explanation:

The electric force exerted on the electron is given by:

F=qE

where

q=1.6\cdot 10^{-19}C is the magnitude of the electron charge

E = 40000 V/m is the electric field

Substituting,

F=(1.6\cdot 10^{-19} C)(40000 V/m)=6.4\cdot 10^{-15} N

By comparison, the gravitational force exerted on the electron is:

F=mg

where

m=9.10939\cdot 10^{-31} kg is the mass of the electron

g = 9.8 m/s^2 is the acceleration due to gravity

Substituting,

F=(9.10939\cdot 10^{-31} kg)(9.8 m/s^2)=8.93\cdot 10^{-30}N

6 0
4 years ago
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