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GuDViN [60]
3 years ago
14

two cars start at the same point and drive in a straight line for 5km. At the end of the drive their distances are the same but

their displacements are different. Explain how this could happen. Illustrate with a diagram.
Physics
1 answer:
Anna11 [10]3 years ago
7 0

A 'displacement' always consists of a magnitude and a direction.  The two cars you just described have displacements with the same magnitude ... 5 km.  But if they didn't both drive in the same direction, then their displacements are different.

Remember:

-- 10 m/s² up and 10 m/s² down are different accelerations

-- 30 mph East and 30 mph West are the same speed but different velocity.

-- 5 km North and 5 km South are the same distance but different displacement.

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A 10 kg ball is traveling at the same speed as a 1 kg ball. Compared to the 10 kg ball, the 1 kg ball has
Colt1911 [192]
We can compare the two by their kinetic energies. The kinetic energy is the energy when an object is in motion. It is expressed as the product of the mass of the object and the square of the velocity divided by two. We assume a velocity of 1 m/s for this problem.<span>

KE = mv^2/2
KE1 = 10 (1)^2
KE1 = 10 J

KE2 = 1(1)^2
KE2 = 1 J

Therefore, c</span><span>ompared to the 10 kg ball, the 1 kg ball has lesser kinetic energy.</span>
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3 years ago
A 0.203-kg plastic ball moves with a velocity of 0.30 m/s. it collides with a second plastic ball of mass 0.092 kg, which is mov
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7 0
3 years ago
A baseball is thrown horizontally from a cliff at 30 m/s and lands 7 seconds after the baseball was thrown. Calculate the horizo
ASHA 777 [7]

Answer:

The horizontal and vertical distances are x = 210 m and y = -240.35 m, respectively.

Explanation:

Using the equation of the displacement in the x-direction, we have:

(let's recall we have a constant velocity in this direction)

x=v_{ix}t

Where:

  • v(ix) is the initil velocity in the x direction (v(ix) = 30 m/s)
  • t is the time (t = 7 s)

x=30(7)    

x=210\: m    

Now, we need to use the equation of the displacement in the y-direction to find the vertical distance. Here we have an acceleration (g)

y=v_{iy}t-\frac{1}{2}gt^2

Where:

  • v(iy) is the initial velocity at the y-direction. In this case, it will be 0
  • t is the time
  • g is the acceleration of gravity (g=9.81 m/s²)

Then, the vertical position at 7 s is:

y=-\frac{1}{2}(9.81)(7)^2

y=-240.35\: m

Therefore, the horizontal and vertical distances are x = 210 m and y = -240.35 m, respectively. The minus sign means the <u>negative value in the y-direction.</u>

I hope it helps you!

7 0
3 years ago
Which of the following BEST summarizes the relationship between groups and culture and critical thinking?
slamgirl [31]

Answer:

Groups and culture helps in influencing our values,ethics and beliefs. This influence should always be questioned through the process of thinking critically.

This best summarizes the relationship between groups and culture and critical thinking.

6 0
3 years ago
A 4g bullet, travelling at 589m/s embeds itself in a 2.3kg block of wood that is initially at rest, and together they travel at
VARVARA [1.3K]

Answer:

The  percentage of the kinetic energy that is left in the system after collision to that before is 0.174 %

Explanation:

Given;

mass of bullet, m₁ = 4g = 0.004kg

initial velocity of bullet, u₁ = 589 m/s

mass of block of wood, m₂ = 2.3 kg

initial velocity of the block of wood, u₂ = 0

let the final velocity of the system after collision = v

Apply the principle of conservation of linear momentum

m₁u₁ + m₂u₂ = v(m₁+m₂)

0.004(589) + 2.3(0) = v(0.004 + 2.3)

2.356 = 2.304v

v = 2.356 / 2.304

v = 1.0226 m/s

Initial kinetic energy of the system

K.E₁ = ¹/₂m₁u₁² + ¹/₂m₂u₂²

K.E₁ = ¹/₂(0.004)(589)² = 693.842 J

Final kinetic energy of the system

K.E₂ = ¹/₂v²(m₁ + m₂)

K.E₂ = ¹/₂ x 1.0226² x (0.004 + 2.3)

K.E₂ = 1.209 J

The kinetic energy left in the system = final kinetic energy of the system

The percentage of the kinetic energy that is left in the system after collision to that before = (K.E₂ / K.E₁) x 100%

                       = (1.209 / 693.842) x 100%

                        = 0.174 %

Therefore, the  percentage of the kinetic energy that is left in the system after collision to that before is 0.174 %

6 0
4 years ago
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