Answer:
The length of river frontage for each lot are 96.55 ft. 98.85 ft, 101.15 ft and 103.45 ft.
Step-by-step explanation:
See the attached diagram.
The river frontage of 400 ft will be divided into 84 : 86 : 88 : 90 for each lot as AP, BQ, CR, DS and ET all are parallel.
Therefore, PQ : QR : RS : ST = 84 : 86 : 88 : 90 = 42 : 43 : 44 : 45
Let, PQ = 42x, QR = 43x, RS = 44x and ST = 45x
So, (42x + 43x + 44x + 45x) = 400
⇒ 175x = 400
⇒ x = 2.2988.
So, PQ = 42x = 96.55 ft.
QR = 43x = 98.85 ft.
RS = 44x = 101.15 ft and
ST = 45x = 103.45 ft
(Answer)
Answer:
38
Step-by-step explanation:
f(x)=6x+2
6x6 (6 sqaured)
f(36)=36x+2
Now we add 36+2
38
First, distribute the 7:
7w + 14 + 0.5w = 5
Combine like terms:
7.5w + 14 = 5
7.5w = -9
Divide both sides by 7.5 to solve for w:
w = -9/7.5 = -1.2
The answer is -1.2
Answer:
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