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3 years ago

There are 180 students in the gym for an assembly. if 5% of them are girls, how many girls are there

Mathematics

2 answers:

Furkat [3]3 years ago

3 0

There are 9 girls in the gym assembly

ahrayia [7]3 years ago

3 0

180 x 5% = 180 x 0.05 = 9 THUS 9 girls of the 180 students are at the assembly

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Stephanie has a photo album with 500 pages each photo takes up 1/3 of a page how many photos can she put in the album

laila [671]

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3 years ago

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Given the function f(x) = 3x + 1, what is the value of f(-2/3)? show work

Marta_Voda [28]

Answer:

f(-2/3) = -1

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Function Notation

Step-by-step explanation:

Step 1: Define

f(x) = 3x + 1

f(-2/3) is x = -2/3

Step 2: Evaluate

Substitute: f(-2/3) = 3(-2/3) + 1
Multiply: f(-2/3) = -2 + 1
Add: f(-2/3) = -1

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3 years ago

Assume that y varies inversely with x. If y=9 when x=7, find y when x=2.

Aleks [24]

Answer:1.56

Step-by-step explanation:

For constant of proportionality of k,

y=(1/k)*x

If y =9,

9=7/k

K=7/9=0.78

y=0.78x

y=0.78*2=1.56

When x

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3 years ago

I need help on question number 26

klemol [59]

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3 years ago

The diameter of a circle has length 12. The center is at*(-5, 2). Give the equation

labwork [276]

Answer:

Equation of the circle is : $x^{2} + 10x + y^{2} -4y -7 =0$

Step-by-step explanation:

Let us consider the image attached in the answer area.

The center O has the co-ordinates i.e. (-5,2) and the diameter given is 12 units.

We know that radius is half of diameter.

$\text{Radius = }\dfrac{\text{Diameter}}{2}$

$\text{Radius = }\dfrac{12}{2}\\\Rightarrow \text{Radius = 6units}$

The equation for circle given the center and radius, can be represented as:

$(x-a)^{2}+ (y-b)^{2} = r^{2}$

Where (a,b) is the co-ordinate of center and r is the radius.

Let us consider the following formula:

$(p+q)^2 = p^{2}+ q^{2} +2pq\\(p-q)^2 = p^{2}+ q^{2} -2pq$

$(x-(-5))^{2}+ (y-2)^{2} = 6^{2}\\\Rightarrow (x+5)^{2}+ (y-2)^{2} = 36\\\Rightarrow x^{2} + 25 + 10x +y^{2} + 4-4y=36\\\Rightarrow x^{2} + 10x +y^{2} -4y-7=0$

Hence, Equation of the circle is : $x^{2} + 10x + y^{2} -4y -7 =0$

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2 years ago