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cupoosta [38]
3 years ago
5

Which set of integers is not a Pythagorean triple?

Mathematics
1 answer:
In-s [12.5K]3 years ago
7 0
<span> B) 14, 46, 48 is not a Pythagorean triplet.</span>
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When a cube with sides numbered one through six is roll one time what is the probability of rolling a four or greater?
Elanso [62]
Since it's a six dice then it's out of x/6

How much is 4 to 6 ?

~3 (counting 4) 4.5.6...

So it's 3/6 = 1/2

3 0
3 years ago
Read 2 more answers
What is the area of this triangle in square units? 10 &amp; 7
ella [17]

Answer: 35

Step-by-step explanation: formula; LxW divided by 2 7x10= 70 70 divided by 2 equals 35

4 0
2 years ago
Read 2 more answers
-
ollegr [7]

Answer:

x = 2

y = -3

z = 4

( 2 , -3, 4 )

Step-by-step explanation:

x + y + z = 3 ---- i

x – y =5 ---- ii

y - z = -7 ---- iii

ii + iii

x - z = -2 ---- iv

i + ii

2x + z = 8 --- v

iv + v

3x = 6

x = 2

x=2 substitute for v

z = 4

x =2 substitute for ii

y = -3

5 0
3 years ago
In Exercises 45–48, let f(x) = (x - 2)2 + 1. Match the<br> function with its graph
MA_775_DIABLO [31]

Answer:

45) The function corresponds to graph A

46) The function corresponds to graph C

47) The function corresponds to graph B

48) The function corresponds to graph D

Step-by-step explanation:

We know that the function f(x) is:

f(x)=(x-2)^{2}+1

45)

The function g(x) is given by:

g(x)=f(x-1)

using f(x) we can find f(x-1)

g(x)=((x-1)-2)^{2}+1=(x-3)^{2}+1

If we take the derivative and equal to zero we will find the minimum value of the parabolla (x,y) and then find the correct graph.

g(x)'=2(x-3)

2(x-3)=0

x=3

Puting it on g(x) we will get y value.

y=g(3)=(3-3)^{2}+1

y=g(3)=1

<u>Then, the minimum point of this function is (3,1) and it corresponds to (A)</u>

46)

Let's use the same method here.

g(x)=f(x+2)

g(x)=((x+2)-2)^{2}+1

g(x)=(x)^{2}+1

Let's find the first derivative and equal to zero to find x and y minimum value.

g'(x)=2x

0=2x

x=0

Evaluatinf g(x) at this value of x we have:

g(0)=(x)^{2}+1

g(0)=1

<u>Then, the minimum point of this function is (0,1) and it corresponds to (C)</u>

47)

Let's use the same method here.

g(x)=f(x)+2

g(x)=(x-2)^{2}+1+2

g(x)=(x-2)^{2}+3

Let's find the first derivative and equal to zero to find x and y minimum value.

g'(x)=2(x-2)

0=2(x-2)

x=2

Evaluatinf g(x) at this value of x we have:

g(2)=(2-2)^{2}+3

g(2)=3

<u>Then, the minimum point of this function is (2,3) and it corresponds to (B)</u>

48)

Let's use the same method here.

g(x)=f(x)-3

g(x)=(x-2)^{2}+1-3

g(x)=(x-2)^{2}-2

Let's find the first derivative and equal to zero to find x and y minimum value.

g'(x)=2(x-2)

0=2(x-2)

x=2

Evaluatinf g(x) at this value of x we have:

g(2)=(2-2)^{2}-2

g(2)=-2

<u>Then, the minimum point of this function is (2,-2) and it corresponds to (D)</u>

<u />

I hope it helps you!

<u />

8 0
3 years ago
What is the sum of the first five terms of a geometric series with a1 = 6 and r = 1/3? Express your answer as an improper fracti
Likurg_2 [28]

Answer:

  242/27

Step-by-step explanation:

Using the formula for the sum, you can fill in the given values and do the arithmetic.

  Sn = a1·(r^n -1)/(r -1)

  S5 = 6·((1/3)^5 -1)/(1/3 -1) = 6(-242/243)/(-2/3) = 6·(121/81)

  S5 = 242/27

_____

Or, you can write the terms and add them up. The sum is ...

  6 + 2 + 2/3 + 2/9 + 2/27 = (162 +54 +18 +6 +2)/27 = 242/27

5 0
3 years ago
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