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3 years ago

G(x)=2(x+4)(x) as a graph

Mathematics

1 answer:

Soloha48 [4]3 years ago

6 0

This isn’t an answer but go on desmos and you should be able to find the graph

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Let p be the plane in space that intersects the x-axis at −5, the y-axis at −2, and the z-axis at 5. Find a vector v¯¯¯ that is

Lana71 [14]

Let P be the plane that intersects

x-axis at point (-5,0,0);
y-axis at point (0,-2,0);
z-axis at point (0,0,5).

Write the equation of the plane P:

$\left|\begin{array}{ccc}x-(-5)&y-0&z-0\\0-(-5)&-2-0&0-0\\0-(-5)&0-0&5-0\end{array}\right|=0\Rightarrow \left|\begin{array}{ccc}x+5&y&z\\5&-2&0\\5&0&5\end{array}\right|=0.$

Then

$-10(x+5)+10z-25y=0,\\ \\2(x+5)-2z+5y=0,\\ \\2x+5y-2z=-10.$

The coefficients at variables x, y and z are the coordinates of perpendicular vector to the plane. Thus

$\vec{v}=(2,5,-2)\perp P.$

Answer: $\vec{v}=(2,5,-2).$

7 0

3 years ago

X=2π/3

Marina86 [1]

Answer:

$cos{\frac{2\pi}{3}}=-\frac{1}{2}$ .

Reference angle is $\frac{\pi}{3}$

Step-by-step explanation:

Given the value of x. we have to find the correct value of cosx.

$x=\frac{2\pi}{3}$

Now, we have to find the exact value of $cos{\frac{2\pi}{3}}$

$cos{\frac{2\pi}{3}}=cos(\frac{\pi}{2}+\frac{\pi}{6})$

$=-sin(\frac{\pi}{6})$

$=-\frac{1}{2}$

Now, we have to find the reference angle of $x=\frac{2\pi}{3}$ .

Since the angle $x=\frac{2\pi}{3}$ lies in second quadrant, the reference angle formula is

Reference angle= $\pi-given angle$ .

= $\pi-\frac{2\pi}{3}=\frac{\pi}{3}$

3 0

3 years ago

Use the identity tan(theta) = sin(theta) / cos(theta) to show that tan(???? + ????) = tan(????)+tan(????) / 1−tan(????) tan(????

VMariaS [17]

Answer:

See the proof below.

Step-by-step explanation:

For this case we need to proof the following indentity:

$tan(x+y) = \frac{tan (x) + tan(y)}{1- tan(x) tan(y)}$

So we need to begin with the definition of tangent, we know that $tan (x) =\frac{sin(x)}{cos(x)}$ and we can do this:

$tan (x+y) = \frac{sin (x+y)}{cos(x+y)}$ (1)

We also have the following identities:

$sin (a+b) = sin (a) cos(b) + sin (b) cos(a)$

$cos(a+b)= cos(a) cos(b) - sin(a) sin(b)$

Now we can apply those identities into equation (1) like this:

$tan (x+y) =\frac{sin (x) cos(y) + sin (y) cos(x)}{cos(x) cos(y) - sin(x) sin(y)}$ (2)

We can divide numerator and denominator from expression (2) by $\frac{1}{cos(x) cos(y)}$ we got this:

$tan (x+y) = \frac{\frac{sin (x) cos(y)}{cos (x) cos(y)} + \frac{sin(y) cos(x)}{cos(x) cos(y)}}{\frac{cos(x) cos(y)}{cos(x) cos(y)} -\frac{sin(x)sin(y)}{cos(x) cos(y)}}$

And simplifying we got:

$tan (x+y) = \frac{tan(x) + tan(y)}{1-tan(x) tan(y)}$

And that complete the proof.

8 0

3 years ago

Pls help I’ll brainlest and add extra points solve it like 7 and 9<br> Just do 1,3,5

alexdok [17]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Let h be the function that assigns each student ID number to a grade level.

denis-greek [22]

Answer:

It is a function Jonny!

Step-by-step explanation:

Hello! I would say to Jonny:

Jonny! A function is a relation between two sets, in which every element of the first set (domain) is assigned only one element of the second set (codomain).

If you have serveral elements of the first set with the same corresponding element of the second set it is correct to call that relation a function.

However, if you have an element of the first set for which your relation can relate to more than one element of the second set, then Jonny, that is not a function.

In the present case, every student ID number can only be realted to a number of the set {9, 10, 11, 12}, a student cannot have more than one current grade level. Therefore, that relation is in fact a function

5 0

3 years ago