You have $15 and admission is $5, so you know have $10 before doing any games. If you wanted to play 12 games, you would need $10.20, which you do not have. But, if you wanted to play 11 games, then you would need $9.35, which is just under $10.
So the maximum amount of games that you could play would be 11 games.
Hello!
First of all let's find the perimeter (circumference) of the semi circles. We can combine them to make one circle with a diameter of 4 (as we can see the side length of one semi circle is 4 cm. We now plug it into the circumference equation (

=3.14).
4(3.14)=12.56
Now we add up the side lengths of the rectangle.
4+6+4+6=20
Now we add up the length of our circle and rectangle.
20+12.56=32.56
Therefore our answer is
32.56 cm.
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Now to find the area! If we combine the two semicircles, we get a circle with a diameter of four. This means that is has a radius of two. We use the equation below to find the area of the two circles.
A=

r²
First we will square our radius.
2(2)=4
Now we multiply by pi.
4(3.14)=12.56
Now we need to find the area of the rectangle.
6(4)=24
Now we add.
24+12.56=
36.56.
I hope this helps!
Answer:
Step-by-step explanation:
This is a special die. Its six sides bear the numbers {9, 10, 11, 12, 13, 14}.
There are three possibilities for getting a multiple of two: {10, 12, 14}, and
there is only one possibilities for getting a multiple of ten: {10, 12, 14}
The probability here of getting a multiple of two is 3/6, and that of getting a multiple of ten is 1/6. But one of the outcomes is found in both result sets: 10. Getting a multiple of 10 is already included in the event that the outcome is a multiple of two. My answer here would be 3/6, or 1/2.
51 x 8 = 408
It can be in this way: 51*8=408