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natali 33 [55]
3 years ago
15

Write y = 2x + 3 using function notation

Mathematics
1 answer:
Darya [45]3 years ago
8 0
F(x) = 2x + 3 i think would be the best way to write it
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Evaluate 3m-n when m=5 and n=1
Whitepunk [10]

Answer:

Basically that’s saying 3 • 5 - 1 which will equal 14

Step-by-step explanation:

3•5 = 15 - 1 = 14

7 0
3 years ago
Solve this please how do you select a image on brainly >~
Paladinen [302]

Answer:

CLICK THE ADD ATTACHMENT

Step-by-step explanation:

3 0
3 years ago
[HELP ASAP 50 POINTS] 17, 18, 19, 20
Charra [1.4K]

17) f(x) = 16/(13-x).

In order to find domain, we need to set denominator expression equal to 0 and solve for x.

And that would be excluded value of domain.

13-x =0

Adding x on both sides, we get

13-x +x = x.

13=x.

Therefore, domain is All real numbers except 13.



18).f(x) = (x-4)(x+9)/(x^2-1).

In order to find the vertical asymptote, set denominator equal to 0 and solve for x.

x^2 -1 = 0

x^2 -1^2 = 0.

Factoring out

(x-1)(x+1) =0.

x-1=0 and x+1 =0.

x=1 and x=-1.

Therefore, Vertical asymptote would be

x=1 and x=-1

19) f(x) = (7x^2-3x-9)/(2x^2-4x+5)

We have degrees of numberator and denominator are same.

Therefore, Horizontal asymptote is the fraction of leading coefficents.

That is 7/2.


20) f(x)=(x^2+3x-2)/(x-2).

The degree of numerator is 2 and degree of denominator is 1.

2>1.

Degree of numerator >  degree of denominator .

Therefore, there would no any Horizontal asymptote.

6 0
3 years ago
Cash Orcheck had a balance of $867 in his checking account on
Nadya [2.5K]

Answer:

Well since he wrote the amount, he’s technically giving cash away so you basically jsut add everything.

98+456+29+381= 964

867-964= -97

His final balance would be -97

Here’s the thing, a checking account acts like a debit card. Its your own cold hard cash. That means you can’t give away more then you have.

So here are the two options

1) At least one or at most 2 checks must’ve bounced

2) He got more money in his checking account

8 0
3 years ago
A continuous random variable X has cdf F(x)=x² b (a) Determine the constants a and b. for a < 0, for 0 < x < 1, for x &
Karolina [17]

Any proper CDF F(x) has the properties

• \displaystyle \lim_{x\to-\infty} F(x) = 0

• \displaystyle \lim_{x\to+\infty} F(x) = 1

so we have to have a = 0 and b = 1.

This follows from the definitions of PDFs and CDFs. The PDF must satisfy

\displaystyle \int_{-\infty}^\infty f(x) \, dx = 1

and so

\displaystyle \lim_{x\to-\infty} F(x) = \int_{-\infty}^{-\infty} f(t) \, dt = 0 \implies a = 0

\displaystyle \lim_{x\to+\infty} F(x) = \int_{-\infty}^\infty f(t) \, dt = 1 \implies b = 1

8 0
2 years ago
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