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Luda [366]
3 years ago
11

A hacker is trying to guess someone's password. The hacker knows (somehow) that the password is 5 digits long, and that each dig

it could be a number between 0 and 4. Assume that the hacker makes random guesses. What is the probability that the hacker guesses the password on his first try?
Mathematics
1 answer:
Sholpan [36]3 years ago
4 0

He might have used Charles?  Or he has hacked before, and is experienced with hacking.

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Represent the following sentence as an algebraic expression, where "a number" is the letter x.
oksano4ka [1.4K]
7+x is the awnser

unless you meant to type “A number is more than 7” then it would be x>7
7 0
2 years ago
Read 2 more answers
Please help i just wanna see if it is D as the answer
3241004551 [841]

Answer:

yes

Step-by-step explanation:

4 0
3 years ago
Solve the following quadratic function
Leya [2.2K]

Answer:

x = ± 10

Step-by-step explanation:

to solve the equation let y = 0 , that is

100 - x² = 0 ( add x² to both sides )

100 = x² ( take square root of both sides )

± \sqrt{100} = x , that is

x = ± 10

8 0
2 years ago
suppose X and Y are independent random variables, both with normal distributions. If X has a mean of 45 with a standard deviatio
djyliett [7]

Answer:

0.9772 = 97.72% probability that a randomly generated value of X is greater than a randomly generated value of Y

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

\mu_X = 45, \sigma_X = 4, \mu_Y = 35, \sigma_Y = 3

What is the probability that a randomly generated value of X is greater than a randomly generated value of Y

This means that the subtraction of X by Y has to be positive.

When we subtract two normal variables, the mean is the subtraction of their means, and the standard deviation is the square root of the sum of their variances. So

\mu = \mu_X - \mu_Y = 45 - 35 = 0

\sigma = \sqrt{\sigma_X^2+\sigma_Y^2} = \sqrt{25} = 5

We want to find P(X > 0), that is, 1 subtracted by the pvalue of Z when X = 0. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{0 - 10}{5}

Z = -2

Z = -2 has a pvalue of 0.0228

1 - 0.0228 = 0.9772

0.9772 = 97.72% probability that a randomly generated value of X is greater than a randomly generated value of Y

4 0
3 years ago
Solve for x I need help on this question
AlexFokin [52]

Answer:

x\approx7.8

Step-by-step explanation:

In relation to the given angle, we are given the triangle's opposite side and hypotenuse. Therefore, we use the sine function to set up a proportion and solve for the opposite side:

sin(\theta)=\frac{opposite}{hypotenuse}

sin(23^\circ)=\frac{x}{20}

20sin(23^\circ)=x

x=20sin(23^\circ)

x\approx7.8

Therefore, the length of the opposite side is about 7.8 units

3 0
2 years ago
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