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mash [69]
3 years ago
8

An athlete runs 90 laps in 6 hours. This is the same

Mathematics
2 answers:
kolezko [41]3 years ago
7 0
Im thinking the answer is c
zhuklara [117]3 years ago
5 0
6*60=360
360/90=1/4
So for 1/4 lap per minute
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Using what you have learned about solving systems of equations, find the number that represents the apple, banana, and cherry.
erica [24]

it would be convenient if you actually give us the equation

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3 years ago
Make 2 sets of data 8 numbers each between 1 and 25. Then calculate the median and IQR for each data set.
vlada-n [284]

The median of the data set will be 15.5. The data set is in between the 1 to 25.

<h3>What is median?</h3>

Median is such a number for the arranged data set in ascending or descending order, such that to its left and to its right belong the same number of observations.

The data set between the number is;

1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25

The value of IQR for data set is;

First Quartile Q1 = 6.5

Second Quartile Q2 = 13

Third Quartile Q3 =19.5

The median of the data set is;

\rm Median= \frac{15+16}{2}  \\\\ Median= 15.5

Hence, the median of the data set will be 15.5.

To learn more about median refer:

brainly.com/question/21396105

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3 0
2 years ago
This is the whole picture can someone help??
Maksim231197 [3]

Step-by-step explanation:

I can't see good the picture

3 0
3 years ago
The equation below shows the relationship between the number of apples purchased, a, and the total cost
inessss [21]

Answer:

C

Step-by-step explanation:

a (5) = c (4)

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20 (total) divided by the 5 apples is $4.

6 0
3 years ago
Read 2 more answers
Six sophomores and 14 freshmen are competing for two alternate positions on the debate team. Which expression represents the pro
Elanso [62]

Answer:

<em>Choose the first alternative</em>

\displaystyle P=\frac{_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C}}{_{2}^{20}\textrm{C}}

Step-by-step explanation:

<u>Probabilities</u>

The requested probability can be computed as the ratio between the number of ways to choose two sophomores in alternate positions (N_s) and the total number of possible choices (N_t), i.e.

\displaystyle P=\frac{N_s}{N_t}

There are 6 sophomores and 14 freshmen to choose from each separate set. There are 20 students in total

We'll assume the positions of the selections are NOT significative, i.e. student A/student B is the same as student B/student A.

To choose 2 sophomores out of the 6 available, the first position has 6 elements to choose from, the second has now only 5

_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C} \text{ ways to do it}

The total number of possible choices is

_{2}^{20}\textrm{C} \text{ ways to do it}

The probability is then

\boxed{\displaystyle P=\frac{_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C}}{_{2}^{20}\textrm{C}}}

Choose the first alternative

7 0
3 years ago
Read 2 more answers
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