keeping in mind that in a parallelogram the diagonals bisect each other, namely cut each other into two equal halves. Check the picture below.
![\stackrel{GH}{3x-4}~~ = ~~\stackrel{HE}{5y+1}\implies 3x=5y+5\implies x=\cfrac{5y+5}{3} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{DH}{x+1}~~ = ~~\stackrel{HF}{3y}\implies \stackrel{\textit{substituting "x" in the equation}}{\cfrac{5y+5}{3}+1~~ = ~~3y}](https://tex.z-dn.net/?f=%5Cstackrel%7BGH%7D%7B3x-4%7D~~%20%3D%20~~%5Cstackrel%7BHE%7D%7B5y%2B1%7D%5Cimplies%203x%3D5y%2B5%5Cimplies%20x%3D%5Ccfrac%7B5y%2B5%7D%7B3%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7BDH%7D%7Bx%2B1%7D~~%20%3D%20~~%5Cstackrel%7BHF%7D%7B3y%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bsubstituting%20%22x%22%20in%20the%20equation%7D%7D%7B%5Ccfrac%7B5y%2B5%7D%7B3%7D%2B1~~%20%3D%20~~3y%7D)
Y = -4/5 x - 2
-9 = -4/5 x - 2
-4/5 x = -9 + 2 = -7
-4x = 5(-7) = -35
x = -35/-4 = 35/4
Answer:
Look below.
Step-by-step explanation:
FYI: Im a bit confused on what this question is asking but I am responding based on what I believe the question is asking.
The point 100 spaces to the left of -1 would be (-101,0) and the point 100 spaces to the left of -1 would be (100,0).
The point(s) 100 spaces to the left of -1 would be (- infinity, -1) and the point(s) 100 spaces to the right would be (-1, infinity).
The sum of the opposite interior angles is equal to the exterior angle.
So,
∠CAB + ∠ACB = ∠CBD
x + 40 + 3x + 10 = 6x
4x + 50 = 6x
2x = 50
x = 25°
∠CAB = x + 40 = 25 + 40 = 65°
Hence, the answer is D.
