Answer:

Step-by-step explanation:
The picture of the question in the attached figure
we know that
----> by SOH (opposite side divided by the hypotenuse)
we have

solve for BC

substitute the values


<u>Supposing 60 out of 100 scores are passing scores</u>, the 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).
- The lower limit is 0.5.
- The upper limit is 0.7.
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the z-score that has a p-value of
.
60 out of 100 scores are passing scores, hence 
95% confidence level
So
, z is the value of Z that has a p-value of
, so
.
The lower limit of this interval is:
The upper limit of this interval is:
The 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).
- The lower limit is 0.5.
- The upper limit is 0.7.
A similar problem is given at brainly.com/question/16807970
Easy.
C
Characterstofilluptherequiredammount
Answer:
There is enough evidence to support the claim
Step-by-step explanation:
We are conduction a hypothesis test for dependent samples. We want to see if there was a change in the test subjects cholesterol levels.
For our situation:
n = 64
d = 0.7
s = 1.72
µ(d) = 0
The hypothesis are:
H0: µ(d) = 0
Ha: µ(d) > 0
This is a right tailed test.
We are testing at the 1% level of significance. Our critical region is z > 2.325
If our test statistic is in this region, we will reject the null hypothesis
See attached photo for the calculation of the test statistic and conclusion of the test
Answer: W=25 and L=50
Step-by-step explanation: I first started out with 50, because 50 is half of 100. 50 divided by 2 equals twenty five. Now, I moved on to 100. 100 divided by 2 equals 50. 25+25+50+50=150.