The cost of 20⅕ oranges is rs 300,what is the cost of a kg oranges?
1 answer:
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(a+b)^7= a^7+ 7a^7b+ 21 a^6b²+ 35a^5b³+ 35 a⁴b⁴+ 21 a³b^5 + 7a²b^6 + b^7
The solution is (3 , 4) ⇒ 2nd answer
Step-by-step explanation:
The system of equations can be solved by:
- Elimination method
- Substitution method
The system of equations is:
y = 3 x - 5 ⇒ (1)
y = x + 3 ⇒ (2)
By using the substitution method substitute y in equation (2) by equation (1)
3 x - 5 = x + 3
Subtract x from both sides
x = 8
Divide both sides by
x = 3
substitute x by 3 in equation (1)
y = 3(3) - 5
y = 9 - 5
y = 4
The solution is (3 , 4)
Learn more:
You can learn more about the system of equations in brainly.com/question/6075514
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