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kumpel [21]
2 years ago
6

If x is -3 and y is 2 what is x ^ 2 + y ^ 2 ​

Mathematics
1 answer:
Pavlova-9 [17]2 years ago
4 0

Answer:

ans=-2

Step-by-step explanation:

-3*2+2*2

=-6+4

=-2

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If f(x) = 3x - 5, than f(2) =
Mamont248 [21]
If we substitute 2 into x it'll be:

3x - 5 \\ 3(2) - 5 \\ 6 - 5 \\ 1

5 0
2 years ago
What is the approximate surface area of the sphere if circumference is 37.68?
damaskus [11]

The surface area of a sphere is  A = 4 π R² .

Sadly, the question doesn't give you 'R', so you have to
back it out of the circumference.

                           Circumference = π (diameter)

Divide each side by π :  Diameter = circumference / π

Radius = 1/2 diameter:  Radius = circumference / (2 π)

                                       Area = 4 π R²  =

                                                 4 π (circumference/2π)² =

                                                 4 π (circumference)² / 4 π²

Divide top and bottom by  4π :  Area = (Circumference)² / π

         Circumference = 37.68 units

         Area =  (37.68)² square units /π =
    
                       <em>451.93 square units</em>


8 0
2 years ago
The vertices of two rectangles are A(−5,−1),B(−1,−1),C(−1,−4),D(−5,−4) and W(1,6),X(7,6),Y(7,−2),Z(1,−2). Compare the perimeters
valkas [14]
The two rectangles are not similar. actually WXYZ is not a rectangle at all. it is a polygon but not a rectangle. hope the visual helps.. 

4 0
3 years ago
Adam is climbing up the stairs in a building. At a certain point, Adam starts counting the steps and when he reaches the last st
Ksivusya [100]

Answer:

He climed 3 steps before he started counting the steps.

Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
Rectangles J and K are similar. If the area of rectangle J is 440, what is the area of rectangle K? I need this today
Hunter-Best [27]

Answer:

Area = 27.5

Step-by-step explanation:

Given

J_{Area} = 440

J_{Width} = 22

K_{Width} = 5.5

<em>See attachment</em>

Required

Determine the area of K

First, we need to calculate the length of the rectangle  J

J_{Length} * J_{Width} = J_{Area}

This gives:

J_{Length} * 22 = 440

Divide both sides by 22

\frac{J_{Length} * 22}{22} = \frac{440}{22}

J_{Length} = 20

So, the length of the rectangle J is 20.

Since both shapes are similar, then:

J_{Length} : J_{Width} = K_{Length} : `K_{Width}

Substitute the known values:

20 : 22 = K_{Length} : `5.5

Express as fraction:

\frac{20 }{ 22 }= \frac{K_{Length} }{ `5.5}

Make Length, the subject of formula

K_{Length} = \frac{5.5 * 20}{22}

K_{Length} = \frac{110}{22}

K_{Length} = 5

The area of K is:

Area = K_{Length} * K_{Width

Area = 5.5 * 5

Area = 27.5

4 0
2 years ago
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