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Answer:
The length of river frontage for each lot are 96.55 ft. 98.85 ft, 101.15 ft and 103.45 ft.
Step-by-step explanation:
See the attached diagram.
The river frontage of 400 ft will be divided into 84 : 86 : 88 : 90 for each lot as AP, BQ, CR, DS and ET all are parallel.
Therefore, PQ : QR : RS : ST = 84 : 86 : 88 : 90 = 42 : 43 : 44 : 45
Let, PQ = 42x, QR = 43x, RS = 44x and ST = 45x
So, (42x + 43x + 44x + 45x) = 400
⇒ 175x = 400
⇒ x = 2.2988.
So, PQ = 42x = 96.55 ft.
QR = 43x = 98.85 ft.
RS = 44x = 101.15 ft and
ST = 45x = 103.45 ft
(Answer)
Answer:
The function that models the depth of the hole in feet over time in hours is .
Step-by-step explanation:
According to the statement, the variable to be modelled is the depth of the hole, which decreases whereas is filled. Under the assumption that the hole is filled at constant rate, we obtain the following expression:
(1)
Where:
- Current depth of the hole, measured in inches.
- Initial depth of the hole, measured in inches.
- Filled level, measured in inches.
- Filling time, measured in hours.
- Time, measured in hours.
If we know that ,
and
, then the function that models the depth of the hole is:
The function that models the depth of the hole in feet over time in hours is .