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2 years ago

⅓ = 1÷3 True or false?

Mathematics

1 answer:

sergey [27]2 years ago

7 0

Answer:

TRUE

Step-by-step explanation:

1/3

1 (divied sign) 3

yes because you ussaly only have to draw the line from the division probvlen

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y = 2x squared + 5x -3 can be written in the form y= 2( x+a) squared + b . Find the value of a and the value of b.

Elan Coil [88]

General vertex form:

$y = m(x − a)² + b \: with \: vertex \: at \: (a, b)$

Given :

$y = 2x² + 5x - 3$

Extract "spread factor" m

$y = 2( x² + \frac{5}{2} x) - 3$

Complete the square

$y = 2(x² + \frac{5}{2}x + ( \frac{5}{4})²) - 3$

$- 2( \frac{5}{4})²$

Write as a squared binomial and simplify the constant

$y = 2(x + \frac{5}{4})² - 6 \frac{1}{8}$

Re-write to match signs of standard general form:

$y = 2(x - ( - \frac{5}{4}))² \: + ( - 6 \frac{1}{8})$

3 0

1 year ago

If sx = 35, then x = 7

Ostrovityanka [42]

Answer:

s=5

Step-by-step explanation:

35 divided by 7 equals 5

8 0

2 years ago

Read 2 more answers

1. You invest $2500 with annual interest rate of 4%. How much money will you have after 5 years?Use the following formula:A = P(

Yuki888 [10]

$ 3042

Explanation

we need to use the formula:

$\begin{gathered} A=P(1+r)^t \\ \text{where} \\ \text{ P is the principal} \\ r\text{ is the rate ( in decimal)} \\ t\text{ is the time} \end{gathered}$

Step 1

a)let

$\begin{gathered} P=2500 \\ r=\text{ 4\% =}\frac{4}{100}=0.04 \\ r=0.04 \\ t=5\text{ ( years)} \end{gathered}$

b) now, replace

$\begin{gathered} A=P(1+r)^t \\ A=2500(1+0.04)^5 \\ A=2500(1.04)^5 \\ A=2500(1.2166) \\ A=3041.63 \\ \text{rounded} \\ A=3042 \end{gathered}$

therefore, the answer is

$ 3042

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9 months ago

Plz, answer this question I need help. I'll mark you as brainliest and give you 5 stars.

jeka57 [31]

Answer:

pretty sure its D but idk

Step-by-step explanation:

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2 years ago

Consider the number lines shown below which shows jump from one number to another. There are four different arrows, starting fro

horsena [70]

Answer:

Step-by-step explanation:

Its number line 2.

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1 year ago