"if z is a standard normal variable, find the probability. the probability that z lies between 0 and 3.01"

Mathematics

1 answer:

spayn [35]3 years ago

5 0

Probability between z = 0 and z = 3.01 is given by

P(0<z<3.01) = P(z<3.01) - P(z<0)

Reading from the z-table, we have
P(z<0) = 0.5
P(z<3.01) = 0.9987

Hence, P(0<z<3.01) = 0.9987 - 0.5 = 0.4987

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