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Yuri [45]
3 years ago
6

"if z is a standard normal variable, find the probability. the probability that z lies between 0 and 3.01"

Mathematics
1 answer:
spayn [35]3 years ago
5 0
Probability between z = 0 and z = 3.01 is given by

P(0<z<3.01) = P(z<3.01) - P(z<0)

Reading from the z-table, we have
P(z<0) = 0.5
P(z<3.01) = 0.9987

Hence, P(0<z<3.01) = 0.9987 - 0.5 = 0.4987

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Varvara68 [4.7K]

Answer:

The center of circle is (0,0)

Step-by-step explanation:

We need to find the center of the circle of the equation x^{2}+y^{2}=4

Since, the general equation of circle is (x-h)^{2}+(y-k)^{2} = r^{2}

Where (h,k) is center of circle and r is radius.

Re-write the circle equation is x^{2}+y^{2}=4 as,

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so, (x-0)^{2}+(y-0)^{2} = 2^{2}

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