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Yuri [45]
3 years ago
6

"if z is a standard normal variable, find the probability. the probability that z lies between 0 and 3.01"

Mathematics
1 answer:
spayn [35]3 years ago
5 0
Probability between z = 0 and z = 3.01 is given by

P(0<z<3.01) = P(z<3.01) - P(z<0)

Reading from the z-table, we have
P(z<0) = 0.5
P(z<3.01) = 0.9987

Hence, P(0<z<3.01) = 0.9987 - 0.5 = 0.4987

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Find the value of the polynomial 5x – 4x^2 + 3 at x = 2 and x = –1​
aliya0001 [1]

Answer:

Let the polynomial be f(x) = 5x – 4x^2 + 3

Now, for x = 2,

f(2) = 5(2) – 4(2)^2 + 3

=> f(2) = 10 – 16 + 3 = –3

Or, the value of the polynomial 5x – 4x^2 + 3 at x = 2 is -3.

Similarly, for x = –1,

f(–1) = 5(–1) – 4(–1^)2 + 3

=> f(–1) = –5 –4 + 3 = -6

The value of the polynomial 5x – 4x2 + 3 at x = -1 is -6.

Answered by GAUTHMATH

6 0
3 years ago
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Answer:

\log_48

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2 years ago
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