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Yuri [45]
3 years ago
6

"if z is a standard normal variable, find the probability. the probability that z lies between 0 and 3.01"

Mathematics
1 answer:
spayn [35]3 years ago
5 0
Probability between z = 0 and z = 3.01 is given by

P(0<z<3.01) = P(z<3.01) - P(z<0)

Reading from the z-table, we have
P(z<0) = 0.5
P(z<3.01) = 0.9987

Hence, P(0<z<3.01) = 0.9987 - 0.5 = 0.4987

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Round 0.74 to the nearest tenth
Nimfa-mama [501]

Answer:

.7

Step-by-step explanation:

if the second number was over 5 then, you would have rounded it to .8, but it was only 4 so you round down.

5 0
3 years ago
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How many meters are there in 33 km?
s2008m [1.1K]
1000 meters make 1km. So let's compare that with the question.
1000m=1km
Y=33km
I represented the unknown with Y. Next, you have to cross and multiply. 33 will multiply 1,000 to give 33,000. And Y will multiply 1 to give Y. That will be;
Y=33,000m
33km makes 33,000m.
Hope that helped. Have a nice day
8 0
3 years ago
Which table of values represents a linear function?
e-lub [12.9K]

Answer:

I don't know it's very hart

8 0
2 years ago
Use a net to find the surface Area of the square pyramid The height of the pyramid is 9 yes and the base sides are all 2.5 yrds
Cerrena [4.2K]

Answer:

Area = 51.68yd^2

Step-by-step explanation:

Given

h = 9yd -- height

a = 2.5yd --- base sides

Required

Determine the surface area

The net is not given. So, I will solve directly.

The surface area is calculated as:

Area = a^2 + 2a\sqrt{\frac{a^2}{4} + h^2}

So, we have:

Area = 2.5^2 + 2*2.5\sqrt{\frac{2.5^2}{4} + 9^2}

Area = 6.25 + 5\sqrt{\frac{6.25}{4} + 81}

Area = 6.25 + 5\sqrt{1.5625 + 81}

Area = 6.25 + 5\sqrt{82.5625}

Area = 6.25 + 5* 9.086

Area = 51.68yd^2

6 0
3 years ago
According to ​Lambert's law​, the intensity of light from a single source on a flat surface at point P is given by Upper L equal
malfutka [58]

Answer:

(a) L = k*(1 - sin^{2}(\theta))        

(b) L reaches its maximum value when θ = 0 because cos²(0) = 1

Step-by-step explanation:

Lambert's Law is given by:

L = k*cos^{2}(\theta)   (1)

(a) We can rewrite the above equation in terms of sine function using the following trigonometric identity:

cos^{2}(\theta) + sin^{2}(\theta) = 1

cos^{2}(\theta) = 1 - sin^{2}(\theta)  (2)

By entering equation (2) into equation (1) we have the equation in terms of the sine function:

L = k*(1 - sin^{2}(\theta))        

(b) When θ = 0, we have:

L = k*cos^{2}(\theta) = k*cos^{2}(0) = k  

We know that cos(θ) is a trigonometric function, between 1 and -1 and reaches its maximun values at nπ, when n = 0,1,2,3...

Hence, L reaches its maximum value when θ = 0 because cos²(0) = 1.

I hope it helps you!

5 0
3 years ago
Read 2 more answers
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