1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sergio [31]
2 years ago
7

write the point slope form of the equation of the line that passes through the points (-3,5) and (-1,4)

Mathematics
1 answer:
Lynna [10]2 years ago
4 0

Answer:

x+2y-7

Step-by-step explanation:

slope (m)=y2-y1/x2-x1

=4-5/-1+3

=-1/2

we have, point slope form of an eqn is

y-y1=m (x-x1)

or, y-5=-1/2 (x+3)

or, 2y-10=-x-3

or, x+2y-7=0 is the required eqn

You might be interested in
What is the best estimate for 34 times 57
daser333 [38]
It would be 1,800 because when you round 34 it becomes 30 and when you round 57 becomes 60 and 30 x 60 = 1,800. This helps me round remember "4 or less let it rest, 5 or more raise the score" hope that makes rounding easier!!
3 0
3 years ago
What percentage of 23 is 924
monitta
Well, the answer to the question in your picture is $1200.

If x is the original price, and we took 23%, or 0.23 from that, we are left with 77%, or 0.77 of the full price.

So 0.77x = 924
x = 924/0.77
x = 1,200

1200 - 0.23(1200) = 924

924 = 0.77x

8 0
2 years ago
Read 2 more answers
I decide to bake some cakes.I need 150g of flour for 12 cakes.How much flour do I need for 30 cakes?
blagie [28]
150 / 12 = 11.6666666667
11.6666666667 x 30 = approximately 350g of flour for 30 cakes
7 0
3 years ago
Using suitable identity find 231^222-131^2​
Sliva [168]

Given:

Consider the expression is

231^2-131^2

To find:

The value of given expression using a suitable identity.

Solution:

We have,

231^2-131^2

Using the identity a^2-b^2=(a-b)(a+b), we get

231^2-131^2=(231-131)(231+131)

231^2-131^2=(100)(362)

231^2-131^2=36200

Therefore, the value of the given expression is 231^2-131^2=36200.

7 0
2 years ago
A) There are 100 students who play at least one of volleyball, soccer and hockey, of these 50 play au three games, 84 play socce
Scilla [17]

Answer:

<h2>i) 3</h2><h2>ii) 5</h2>

Step-by-step explanation:

Let H be the set of students who play Hokey

     V be the set of students who play Volleyball

     S be the set of students who play Soccer

======================================

card(volleyball only) = card(V) - [card(V∩H∩S) + card(V∩H only) + card(V∩S only)]

                                 = 73 - [50 + (58-50) + (62-50)]

                                 = 73 - [50 + 8 + 12]

                                 = 73 - 70

                                 = 3

………………………………………………

Card(Hokey only) = 100 - [3 + 8 + 50 + 10 + 12 + 12]

                              = 100 - 95

                              = 5

…………………

<u><em>Note</em></u> :

A Venn diagram might be helpful in such case.

5 0
2 years ago
Other questions:
  • Which of the following terminating decimals is equivalent to 3/8? 0.250 0.375 0.380 0.830
    15·2 answers
  • The circle graph shows how a family spends its annual income. If $26,450 is used for Auto and Entertainment combined, what is th
    10·1 answer
  • What is the explicit rule for the geometric sequence? 4.05, 1.35, 0.45, 0.15, ...
    11·1 answer
  • If the balance at the end of eight years on an investment of $230 that has been invested at a rate of 3% is $285.20, how much wa
    11·2 answers
  • If the pattern below follows the rule "Starting with five, every consecutive line has a number one more than the previous line,"
    13·1 answer
  • Studies on a bottle-filling machine indicate that it fills bottles to a mean of 16 ounces with a standard deviation of 0.10 ounc
    8·1 answer
  • Please help me with this question
    11·2 answers
  • What would be the value of x please help
    7·1 answer
  • What are the values of v and w?
    7·2 answers
  • What is the length of the altitude of the equilateral triangle below?​
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!