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3 years ago

Chemical formula selenium dioxide

Chemistry

2 answers:

Schach [20]3 years ago

7 0

Se02 is the formula for selenium dioxide, hope this helped.

jek_recluse [69]3 years ago

5 0

Im pretty sure that se02 is the formula

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Determine the limiting reactant (lr) and the mass (in g) of nitrogen that can be formed from 50.0 g n2o4 and 45.0 g n2h4. some p

Licemer1 [7]

N2O4(l) + 2 N2H4(l) → 3 N2(g) + 4 H2O(g)
1) to calculate the limiting reactant you need to pass grams to moles.
 moles is calculated by dividing mass by molar mass

mass of N2O4: 50.0 g
molar mass of N2O4 = 92.02 g/mol
molar mass of N2H4 = 32.05 g/mol.
mass of N2H4:45.0 g

moles N2O4=50.0/92.02 g/mol= 0,54 mol of N2O4
moles N2H4= 45/32.05 g/mol= 1,40 mol of N2H4

 2)
By looking at the balanced equation, you can see that 1 mol of N2O4 needs 2 moles of N2H4 to fully react . So to react 0,54 moles of N2O4, you need 2x0,54 moles of N2H4 moles
N2H4 needed = 1,08 moles.
You have more that 1,08 moles N2H4, so this means the limiting reagent is not N2H4, it's N2O4. The molecule that has molecules that are left is never the limiting reactant.

3) 1 mol of N2O4 reacting, will produce 3 mol of N2 (look at the equation)
There are 0,54 mol of N2O4 available to react, so how many moles will produce of N2?
1 mol N2O4------------3 mol of N2
0,54 mol N2O4--------x
x=1,62 mol of N2

4) the only thing left to do is convert the moles obtained, to grams.
We use the same formula as before, moles equal to mass divided by molar mass.
$moles= \frac{grams}{molar mass}$ (molar mass of N2= 28)
1,62 mol of N2= mass/ 28
mass of N2= 45,36 grams

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4 years ago

As the mass of the nucleus increases, what happens to the ratio of neutrons to protons in stable isotopes? A. The neutron:proton

vladimir1956 [14]

Propeen is nute 18?.9

8 0

3 years ago

Classify each as the following:element, compound, or mixture:

Studentka2010 [4]

1. element
2. compound
3. element
4. compound
5. compound
6. compound

basically, if its on the periodic table, its an element. for example, rock can be made of many things in the periodic table, therefore its a compound. salt, is NaCl, which are two elements put together, therefore its a compound.

6 0

3 years ago

What is the maximum mass of pure gold that could be extracted from 3.0kg of calaverite, a gold ore with the chemical formula AuT

Marina86 [1]

Answer:

1.3 × 10³ g

Explanation:

Step 1: Convert the mass of calaverite to grams

We will use the relationship 1 kg = 1,000 g.

$3.0kg \times \frac{1,000g}{1kg} = 3.0 \times 10^{3} g$

Step 2: Establish the appropriate mass ratio

The mass ratio of AuTe₂ to Au is 452.17:196.97.

Step 3: Calculate the maximum mass of pure gold that can be obtained from 3.0 × 10³ g of calaverite

$3.0 \times 10^{3} g Calaverite \times \frac{196.97gAu}{452.17gCalaverite} = 1.3 \times 10^{3} gAu$

3 0

4 years ago

What is the frequency of electromagnetic radiation needed to excite an electron in a hydrogen atom from the n = 3 orbit to the n

Andreas93 [3]

The energy of 800 milimoles of photons is 1.38 * 10^-19 J.

<h3>What is excitation of electrons?</h3>

We know that an electron can move from a lower to higher energy level according to the formula;

1/λ = RH(1/ni^2 - 1/nf^2)

RH = 1.097 * 10^7m-1

ni = 3

nf = 6

Thus;

1/λ = 1.097 * 10^7(1/3^2 - 1/6^2)

1/λ = 1.097 * 10^7(1/9 - 1/36)

1/λ = 1.097 * 10^7(0.11 - 0.03)

λ =1.14 * 10^-6 m

v = λf

f = v/λ

f = 3 * 10^8 m/s/1.14 * 10^-6 m

f = 2.6 * 10^14 Hz

Now

E = hf

E= 6.63 * 10^-34 * 2.6 * 10^14 Hz

E = 1.72 * 10^-19 J

Now;

1 mole of photons has 1.72 * 10^-19 J of energy

800 * 10^-3 moles of photons has 800 * 10^-3 moles * 1.72 * 10^-19 J/ 1 mole

= 1.38 * 10^-19 J

Learn more about energy of photons:brainly.com/question/2393994

#SPJ1

5 0

2 years ago