All categories

3 years ago

What is the molarity of a 4.447 L solution

Chemistry

1 answer:

igomit [66]3 years ago

4 0

Answer:52M

Explanation:

use S= 1000w/ MV

Here, s= molarity

w= the amount of NaCl

M= the atomic mass of NaCl

V= the volume of solution

You might be interested in

Examplle of exchange reaction

boyakko [2]

An exchange reaction consists of both synthesis and decomposition reactions.
Here’s a complex example: AB + CD → AC + BD.
Another example might be: AB + CD → AD + BC.

7 0

3 years ago

What is the concentration (m) of sodium ions in 4.57 l of a 2.35 m na3p solution?

Leokris [45]

Answer: 1.03 x 10^25 ions Na

5 0

3 years ago

Read 2 more answers

Given the following equilibrium constants: Kb B(aq) + H2O(l) ⇌ HB+(aq) + OH−(aq) 1/Kw H+(aq) + OH−(aq) ⇌ H2O(l) What is the equi

bija089 [108]

Answer: The value of $K_c$ for the net reaction is $\frac{K_b}{K_w}$

Explanation:

The given chemical equations follows:

Equation 1: $B(aq.)+H_2O(l)\rightleftharpoons HB^+(aq.)+OH^-(aq.);K_b$

Equation 2: $H^+(aq.)+OH^-(aq.)\rightleftharpoons H_2O(l);\frac{1}{K_w}$

The net equation follows:

$B(aq.)+H^+(aq.)\rightleftharpoons HB^+(aq.);K_c$

As, the net reaction is the result of the addition of first equation and the second equation. So, the equilibrium constant for the net reaction will be the multiplication of first equilibrium constant and the second equilibrium constant.

The value of equilibrium constant for net reaction is:

$K_c=K_1\times K_2$

We are given:

$K_1=K_b$

$K_2=\frac{1}{K_w}$

Putting values in above equation, we get:

$K_c=K_b\times \frac{1}{K_w}=\frac{K_b}{K_w}$

Hence, the value of $K_c$ for the net reaction is $\frac{K_b}{K_w}$

7 0

3 years ago

Precision Problems:

Lorico [155]

Answer:

$Precision = 2.70 \± 0.1\ cm$

Explanation:

Given

The data in the table

Required

Follow the steps appended to the question;

Step 1: Calculate the Mean or Average

Mean = Summation of lengths divided by number of teams;

$Mean = \frac{2.65 + 2.75 + 2.80 + 2.77 + 2.60 + 2.65 + 2.68}{7}\ cm$

$Mean = \frac{18.9}{7}\ cm$

$Mean = 2.70\ cm$

Step 2: Get The Range

$Range = Highest - Lowest$

$Range = 2.80cm - 2.60cm$

$Range = 0.2\ cm$

Step 3: Divide Range by 2

$Approximate\ Range = \frac{1}{2}Range$

$Approximate\ Range = \frac{1}{2} * 0.2\ cm$

$Approximate\ Range = 0.1\ cm$

Step 4: Determine the Precision

$Precision = Average \± Approximate\ Range$

Substitute 2.70 for Average and 0.1 for Approximate Range

$Precision = 2.70 \± 0.1\ cm$

4 0

3 years ago

Why do substances burn with or without flame?

Gala2k [10]

Flame (fire) is the effect of a chemical reaction that produces visible light and heat. The chemical reaction is going on in the substance being burned.. Thats why coals glow and flames seem to leap into the air.

If your reaction does not have a flame, then either it is not producing visible light or the reaction does not occur in the air above the substance.

7 0

3 years ago

Read 2 more answers