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MakcuM [25]
3 years ago
7

What is the molarity of a 4.447 L solution

Chemistry
1 answer:
igomit [66]3 years ago
4 0

Answer:52M

Explanation:

use S= 1000w/ MV

Here, s= molarity

w= the amount of NaCl

M= the atomic mass of NaCl

V= the volume of solution

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Menthol is a flavoring agent extracted from peppermint oil. it contains c, h, and o. in one combustion analysis, 10.00 mg of the
marishachu [46]
Combustion reaction for menthol is as follows;
CxHyOz + O₂ ---> xCO₂ +  H₂O
Mass of CO₂ formed - 28.16 mg
Therefore number of moles formed - 28.16/ 44 g/mol = 0.64 mmol
Mass of water formed  - 11.53 mg
number of water moles formed - 11.53 mg/18 g/mol = 0.64 mmol
From CO₂,
1 mol of CO₂ - 1 mol of C and 2 mol of O
therefore number of C moles - 0.64 mmol
                                 O moles - 1.28 mmol
from H₂O
1 mol of H₂O - 2 mol of H and 1 mol of O
number of H moles - 1.28 mmol
                 O moles - 0.64 mmol

Mass of menthol initially - 10 mg
in reactions, the masses of products are equal to the masses of reactants. The excess mass to the products formed is due to O₂ in air
Original mass of menthol - 10 mg
mass of water and CO₂ - 11.53 mg + 28.16 mg = 39.69
Difference in mass - 39.69 - 10 = 29.69 mg
This difference comes from O moles in air - 29.69 mg/ 16 g/mol = 1.8556 mmol
then O moles coming from menthol - (1.28 + 0.64) - 1.8556 = 0.064 mmol

In menthol 
C moles - 0.64 mmol
H moles - 1.28 mmol
O moles - 0.064 mmol
ratios of C:H:O
C          H         O
0.64    1.28      0.064
x1000  x1000    x1000 to get whole numbers
640       1280      64
10          20          1
Simplest ratio of C:H:O is 10:20:1
therefore empirical formula of menthol is C₁₀H₂₀O


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