Answer:
HHH, W = 3-0 = 3
HHT, W= 2-1=1
HTH, W= 2-1=1
THH, W=2-1 =1
HTT, W= 1-2=-1
THT, W= 1-2=-1
TTH, W=1-2=-1
TTT, W=0-3 = -3
So then the sample space for W is:
Just 4 possible values from 8 possible combinations for the 3 random tosses
Step-by-step explanation:
For this case we define W as the random variable who represent the number of heads minus the number of tails in three tosses of a coin.
W= # heads- # coins
Since we toss a coin 3 times we have 2*2*2= 8 possible results. We can list the results and the corresponding values for W like this:
HHH, W = 3-0 = 3
HHT, W= 2-1=1
HTH, W= 2-1=1
THH, W=2-1 =1
HTT, W= 1-2=-1
THT, W= 1-2=-1
TTH, W=1-2=-1
TTT, W=0-3 = -3
So then the sample space for W is:
Just 4 possible values from 8 possible combinations for the 3 random tosses
It’s either C or D, but i’m pretty sure it’s C
They are equal to one another because 4(3+x) can be rewritten using the distributive property as 4(3)+4x or 3+3+3+3+x+x+x+x
Answer:
probability that a randomly selected page that contains only text will contain no typos that is
P(x=0) = = 0.923
Step-by-step explanation:
<u>Poisson distribution</u>:-
Explanation of the Poisson distribution :-
The Poisson distribution can be derived as a limiting case of the binomial
distribution under the conditions that
i) p is very small
ii) n is very large
ii) λ = np (say finite
The probability of 'r' successes =
Given the average number of typos ∝ = 0.08 per page.
probability that a randomly selected page that contains only text will contain no typos that is =
After calculation P(x=0) = = 0.923
probability that a randomly selected page that contains only text will contain no typos =0.923
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