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alexira [117]
3 years ago
8

Point A is located at (0, -2) and is rotated 180°. What are the coordinates of point A'?

Mathematics
2 answers:
nalin [4]3 years ago
7 0

Answer:

(0,2)

Step-by-step explanation:

Rule for a rotation of 180° about the origin: (x,y)\rightarrow(-x,-y)

We are given the point (0, -2).

Applying the rule:

(0,-2)\rightarrow(0,2)

A' should be at (0,2).

Naya [18.7K]3 years ago
4 0

Answer: The coordinates will be  (0,2) after a  180 degrees rotation.

Step-by-step explanation:

                  90         180

 (0,-2) →    ( -2,0)→   ( 0,2)

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Step-by-step explanation:

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2 years ago
There's a pair of points (3,5), (x,15) and a slope of 2 how do I find x​
sergeinik [125]

You have the slope and you have two points, so you can use the slope equation to find x.

b=\frac{(y_2-y_1)}{(x_2-x_1)} \\2=\frac{(15-5)}{(x-3)} \\2(x-3)=(15-5)\\2x-6=10\\2x=16\\x=8

So your answer is x = 8.

8 0
3 years ago
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If z is inversely proportional to r, and z= 32 when r=1.5, find r when z=8.
lions [1.4K]
Inversely proportional: z = k/r
k = 32 * 1.5 = 48
Plug that into equation
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8 0
3 years ago
Which formula can be used to find the nth term of a geometric sequence where the fifth term is 1/6 and the common ratio is 1/4?
OlgaM077 [116]

Answer:

a_n = 16(\frac{1}{4})^{n - 1}

Step-by-step explanation:

Given:

Fifth term of a geometric sequence = \frac{1}{16}

Common ratio (r) = ¼

Required:

Formula for the nth term of the geometric sequence

Solution:

Step 1: find the first term of the sequence

Formula for nth term of a geometric sequence = ar^{n - 1}, where:

a = first term

r = common ratio = ¼

Thus, we are given the 5th term to be ¹/16, so n here = 5.

Input all these values into the formula to find a, the first term.

\frac{1}{16} = a*\frac{1}{4}^{5 - 1}

\frac{1}{16} = a*\frac{1}{4}^{4}

\frac{1}{16} = a*\frac{1}{256}

\frac{1}{16} = \frac{a}{256}

Cross multiply

1*256 = a*16

Divide both sides by 16

\frac{256}{16} = \frac{16a}{16}

16 = a

a = 16

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nth term = ar^{n - 1}

nth term = 16*\frac{1}{4}^{n - 1}

a_n = 16(\frac{1}{4})^{n - 1}

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3 years ago
What are the coordinates of the point labeled C in the graph?
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