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FromTheMoon [43]
3 years ago
6

How many integers between 8 and 43, inclusive, have a remainder of zero when divided by 4 ?

Mathematics
1 answer:
alisha [4.7K]3 years ago
4 0
8/4=2
12/4=3
16/4=4
20/4=5
24/4=6
28/4=7
32/4=8
36/4=9
40/4=10

Your answer would be C. 9
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Which of the following are the roots of 3x^2-10x+5
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8 0
3 years ago
Determine the value of g(4), g(3 / 2), g (2c) and g(c+3) then simplify as much as possible.
jeka94

Answer:

g(4) = 8 \pi h\\\\g(\frac{3}{2}) = 3 \pi h\\\\ g(2c) = 4 \pi ch\\\\g(c+3) = 2 \pi hc+6\pi h

Step-by-step explanation:

You need to substitute r=4 into g(r) = 2 \pi r h. Then:

g(4) = 2 \pi(4)h\\\\g(4) = 8 \pi h

Substitute r=\frac{3}{2} into g(r) = 2 \pi r h. Then:

g(\frac{3}{2}) = 2 \pi(\frac{3}{2})h\\\\g(\frac{3}{2}) = 3 \pi h

Substitute r=2c into g(r) = 2 \pi r h. Then:

g(2c) = 2 \pi(2c))h\\\\g(2c) = 4 \pi ch

Substitute r=c+3 into g(r) = 2 \pi r h. Then:

g(c+3) = 2 \pi (c+3)h\\\\g(c+3) = 2 \pi hc+6\pi h

8 0
3 years ago
Read 2 more answers
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