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Vanyuwa [196]
3 years ago
6

On a coordinate plane, a solid straight line has a positive slope and goes through (0, negative 1.3) and (3, negative 0.3). Ever

ything below and to the right of the line is shaded.
Which linear inequality is represented by the graph?

y ≤ One-thirdx – 1.3
y ≤ One-thirdx – Four-thirds
y ≥ One-thirdx – Four-thirds
y ≥ One-thirdx – 1.3
Mathematics
2 answers:
blsea [12.9K]3 years ago
7 0

Answer:

A

Step-by-step explanation:

slope=\frac{-0.3-(-1.3)}{3-0}=\frac{1}{3}\\eq.~of~line~is y-(-1.3)=\frac{1}{3}(x-0)\\y=\frac{1}{3}x-1.3\\as~it~is~shaded~to~the~right~so~y\leq \frac{1}{3}x-1.3~satisfies ~it.

Nat2105 [25]3 years ago
7 0

Answer:

A. y\leq \frac{1}{3}x-1.3.

Step-by-step explanation:

We have been given that or a coordinate plane, a solid straight line has a positive slope and goes through (0, -1.3) and (3, -0.3). Everything below and to the right of the line is shaded. We are asked to choose the inequality that represents the graph.    

First of all, we will find the slope of line using our given points as:

m=\frac{-0.3-(-1.3)}{3-0}

m=\frac{-0.3+1.3}{3}

m=\frac{1}{3}

Now we will use point-slope form of equation to find the equation of boundary line as:

y-y_1=m(x-x_1)

y-(-1.3)=\frac{1}{3}(x-0)

y+1.3=\frac{1}{3}x

y+1.3-1.3=\frac{1}{3}x-1.3

y=\frac{1}{3}x-1.3  

The one side of line would be y\geq \frac{1}{3}x-1.3 and other side of the boundary line would be y\leq \frac{1}{3}x-1.3.  

Now we will graph our line.

We can see that the point (0,6) is on right side of boundary line, so we will test (0,6) in both inequalities.

6\leq \frac{1}{3}(0)-1.3

6\leq 0-1.3

6\leq -1.3

Since point (0,6) satisfies the inequality y\leq \frac{1}{3}x-1.3, therefore, our required inequality would be y\leq \frac{1}{3}x-1.3 and option A is the correct choice.

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Given:

The side of a square a, s+3.

The perimeter of a square is the sum of the four sides of the square. Hence,

\begin{gathered} P=s+3+s+3+s+3+s+3 \\ =4(s+3) \end{gathered}

5 0
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ziro4ka [17]

Answer:

48x -5

Step-by-step explanation:

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A person bought some cosmetics from wholesale market at the rate of Rs 360 per dozen he sells it at Rs 80 a pair find the gain p
marusya05 [52]

Answer:

33.33%

Step-by-step explanation:

We need to calculate the <u>unit selling price and cost of each cosmetics.</u>

If a person bought some cosmetics from wholesale market at the rate of Rs 360 per dozen., then for 1 cosmetics, we will say;

x = 1 cosmetic

since 360 = 12 cosmetic

cross multiply

12x = 360

x = 360/12

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Hence the unit cost price of the cosmetics will be Rs. 30

Similarly, if he sells it at Rs 80 a pair, then he sold one cosmetic at 80/2 = Rs. 40 (a pair is 2 cosmetics)

Selling price per unit = Rs. 40

Cost price per unit = Rs. 30

percent gain = SP-CP/CP * 100%

percent gain = 40-30/30 * 100

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Hence the percentage gain is 33.33%

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Anna11 [10]

Answer:

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Step-by-step explanation:

First of all, you already know that 1 pound equals $5.95. Secondly, you have to solve 5.95 divided by 10, which is 0.595. However, the question is asking for 0.2 pounds! Therefore, 0.595 * 2 = 1.19.

But we're not done yet! We still have to find the amount of money in all. 5.95 * 1.19 = 7.0805 The sum of money in all is $7.0805

Hope this helps!

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