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Lorico [155]
3 years ago
13

Mixed numbers between 0 and 2, with a interval of 1/3 between each pair of mixed numbers

Mathematics
2 answers:
expeople1 [14]3 years ago
7 0
Mixed numbers between 0 and 2...with interval of 1/3...
1 1/3 , 1 2/3
stepladder [879]3 years ago
7 0

Answer:

The numbers are: 1\frac{1}{3},1\frac{2}{3}.

Step-by-step explanation:

Consider the provided numbers.

Mixed number is the sum of a whole number and a fraction.

We need to find the mixed number between 0 and 2, the smallest mixed number should be greater than 1(between 0 and 2).  Because if we add a fraction to 0 it will gives us that fraction, not a mixed number.

We want to use the interval of 1/3 between each pair of mixed numbers;

So, The number form as:

1+\frac{1}{3},1+\frac{1}{3}+\frac{1}{3}

1+\frac{1}{3},1+\frac{2}{3}

1\frac{1}{3},1\frac{2}{3}

Thus, the numbers are:  1\frac{1}{3},1\frac{2}{3}.

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Step-by-step explanation:

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Given

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20y = - x - 24 ( add x to both sides )

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What is the remainder R when the polynomial p(x) is divided by (x + 1)? Is (x + 1) a factor of p(x)? p(x) = -3x4 + 2x3 - x2 + 6
vodka [1.7K]

Answer:

(x+1) is a factor with remainder 0.

Step-by-step explanation:

We divide (x+1) into the polynomial -3x^4+2x^3-x^2+6 through long division or synthetic. We choose long division and look for what will multiply with (x+1) to make the polynomial -3x^4+2x^3-x^2+6 .

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We subtract this from the original -3x^4-(-3x^4)+2x^3-(-3x^3)-x^2+6.

This leaves 5x^3-x^2+6. We repeat the step above.

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We subtract this from 6x-(6x)+6-(6)=0. There is no remainder. This means (x+1) is a factor.


7 0
3 years ago
5-2x3+6(3^2+1) =59 need help ??
Temka [501]
5-2*3+6(3^2+1)
5-2*3+6(10)
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59

59=59
True
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