We know that
surface area=area of the base+4*[area of one lateral triangle side]
area of the base=b²
b is the side length of the square
b=14 cm
area of the base=14²-----> 196 cm²
area of one lateral triangle side=b*h/2
b is the side length of the square
b=14 cm
h is the height of the lateral triangle side
h is equal to the slant height
h=15 cm
area of one lateral triangle side=14*15/2----> 105 cm²
surface area=196+4*[105]------> 616 cm²
the answer is
the surface area is 616 cm²
Answer:
angles 1, 3, 6, 8 = 142°
angles 2, 4, 5, 7 = 38°
Step-by-step explanation:
Vertical angles and corresponding angles are congruent, as are alternate interior angles. Hence the angles 1, 3, 6, 8 are all congruent:
∠1 = ∠3 = ∠6 = ∠8 = 142°
Each of the remaining angles forms a linear pair with one or another of those, so is its supplement:
∠2 = ∠4 = ∠5 = ∠7 = 180° -142° = 38°
40/100×120=4/1×12=48. 1/4×200=50. so 1/4 of 200 is greater than 40% of 120.
<h3>Given</h3>
A(-3, 1), B(4, 5)
<h3>Find</h3>
coordinates of P on AB such that AP/PB = 5/2
<h3>Solution</h3>
AP/PB = 5/2 . . . . . desired result
2AP = 5PB . . . . . . multiply by 2PB
2(P-A) = 5(B-P) . . . meaning of the above
2P -2A = 5B -5P . . eliminate parentheses
7P = 2A +5B . . . . . collect P terms
P = (2A +5B)/7 . . . .divide by the coefficient of P
P = (2(-3, 1) +5(4, 5))/7 . . . . substitute the given points
P = (-6+20, 2+25)/7 . . . . . . simplify
P = (2, 3 6/7)