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Yanka [14]
3 years ago
14

Please help with this problem picture will be posted A.S.A.P.

Mathematics
1 answer:
balu736 [363]3 years ago
7 0
I would say B but I can't see the question very well.
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What is the answer to 153÷1/4=?
sp2606 [1]

Answer: 38.25

Step-by-step explanation: You divide the whole number by the denominator in the fraction.

153/4 = 38.25

7 0
2 years ago
Read 2 more answers
How many solutions y= -2x -4 and y=3x plus 3
Oksi-84 [34.3K]

Answer:

The number of solutions is one

Step-by-step explanation:

Here, we want to get the number of solutions

since the linear equations are not the same, neither do they have the same x-variable, we can have only one solution

6 0
2 years ago
A youth ice hockey game has 3 periods that are each 20 minutes long. Colin plays 12 minutes each period. Which ratio shows Colin
labwork [276]
The answer is 12:20.......................

4 0
3 years ago
Read 2 more answers
Can someone help me with this problem://
fiasKO [112]

You can simply collect terms, subtract the constant and divide by the x-coefficient. It is generally considered easier to do those steps if you eliminate fractions first (multiply by 12).

Multiply by 12

... 4(x -1) +3(x +5) = 6

... 4x -4 +3x +15 = 6 . . . . . eliminate parentheses

... 7x +11 = 6 . . . . . . . . . . . .collect terms

... 7x = -5 . . . . . . . . . . . . . . subtract the constant 11

... x = -5/7 . . . . . . . . . . . . . divide by the x-coefficient

_ _ _ _ _ _ _

Here it is the other way.

... x(1/3 +1/4) +(-1/3 +5/4) = 1/2

... (7/12)x + 11/12 = 1/2 . . add the fractions to finish collecting terms

... x + 11/7 = 6/7 . . . . . . . multiply by 12/7

... x = -5/7 . . . . . . . . . . . subtract 11/7

At the third step here, you could subtract 11/12 before doing the multiply. You get the same answer, but you have to do the extra conversion of 1/2=6/12.

8 0
3 years ago
Triangle ABC has side lengths: AB = 3.5 cm, BC = 2.4 cm, and AC = 4.2 cm ΔABC ≅ ΔHJK What is the length of side HJ?
Licemer1 [7]
For this you'll want to draw out Triangle ABC and label it as the problem gives you.

Draw a similar triangle to the first one you drew and label it the exact same way as "ABC" and then match the measurement "AB" to "HJ".

Hope this helps.
4 1
3 years ago
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