Answer:
6.83 units
Step-by-step explanation:
Let the height of the original pyramid be represented by h. Then the cut off top has a height of (h -2). The scale factor for the area is the square of the scale factor for height, so we have ...
(height ratio)^2 = 1/2
((h -2)/h)^2 = 1/2
(h -2)√2 = h . . . . . . square root; multiply by h√2
h(√2 -1) = 2√2 . . . . add 2√2 -h
h = (2√2)/(√2 -1) ≈ 6.8284 . . . units
The altitude of the original pyramid is about 6.83 units.
A line that is parallel to another line will have the same slope, in our case, the slope of 3. Therefore, we can just change the y-intercept to create any line parallel to y=3x+5 (just remember to keep the slope the same). For example, y=3x+5, y=3x-9, and y=3x+6.2 are all equations that are parallel to y=3x+5.
:)
You know the adjacent and you need to find the opposite, so you would use tangent. Your equation would look like this; tan 26°= x/28. You would need to multiply both sides by 28 to simplify it to this; 28*tan 26°= x
Solving this, you would get an answer of 13.7
Answer:y=1/2
Step-by-step explanation:
