Ron now has a 6 by 13 chocolate bar and his goal is to split it into a 1 by 1 square for his family. This means that
<em />we need to look for the area!Although we don't stop there. We might be tempted to assume that the product of 6 and 13 is the answer, but we need to consider that, for the last two remaining squares, Ron will only need to break the bar once, therefore only having to break the chocolate bar one less than its area.
With that in mind, the answer will simply be
.
Answer: 77 times!If you still don't get it, think small! Notice that, for a chocolate bar 2 squares high and 2 squares long, you will only need to break it 3 times in order to have individual squares. The same thing applies for the problem.
Answer:
2.2 metres squared
Step-by-step explanation:
We need to find the area of this trapezoid.
The area of a trapezoid is denoted by:
, where and are the parallel bases and h is the height
Here, we already know the lengths of the two bases; they are 0.9 metres and 2.3 metres. However, we need to find the length of the height.
Notice that one of the angles is marked 45 degrees. Let's draw a perpendicular line from top endpoint of the segment labelled 0.9 to the side labelled 2.3. We now have a 45-45-90 triangle with hypotenuse 2.0 metres. As one of such a triangle's properties, we can divide 2.0 by √2 to get the length of both legs:
2.0 ÷ √2 = √2 ≈ 1.414 ≈ 1.4
Thus, the height is h = 1.4 metres. Now plug all these values we know into the equation to find the area:
The answer is thus 2.2 metres squared.
<em>~ an aesthetics lover</em>
Answer:
2
Step-by-step explanation:
1/6 divided by 1/12
=1/6*12/1
which if you divide 12 by six, equals 2
Answer:
8.25
Step-by-step explanation:
Answer:
D.) A cube that is 1 inch long, 1 inch wide, and 1 inch high
Step-by-step explanation:
A unit cube, more formally a cube of side 1, is a cube whose sides are 1 unit long. The volume of a 3-dimensional unit cube is 1 cubic unit, and its total surface area is 6 square units.
⭐ Answered by Kakashi ʕ •㉨• ʔ⭐
⭐ Brainliest would be appreciated,
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⭐ If you have questions, leave a comment, I'm happy to help! ⭐