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3 years ago

Lauren spent 3/5 of her money on a refrigerator. The refrigerator cost $756. How much money did she have left?

1 answer:

3 0

Fractions are the part/whole. We can set this up to be...

3/5 = 756
756 x5/3 = 1260.

if she had 1260 to begin with and spent 756, she would have 504.00 left.

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Vending machines can be adjusted to reject coins above and below certain weights. The weights of legal U.S. quarters have a norm

tigry1 [53]

Answer: The percentage of legal quarters will be rejected by the vending machine = 2.275%

Step-by-step explanation:

Given: The weights of legal U.S. quarters have a normal distribution with a mean of 5.67 grams and a standard deviation of 0.07 gram.

Let x be the weights of legal U.S. quarters .

Required probability: $P(x5.81)$

$=P(\dfrac{x-\mu}{\sigma}\dfrac{5.81-5.67}{0.07})\\\\=P(z2)\approx0.02275 \ \ \ [By\ P-value\ calculator]$

The percentage of legal quarters will be rejected by the vending machine = 2.275%

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2 years ago

Inverse of y=x^2-10x

Fittoniya [83]

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2 years ago

What is 3 1/5 times 1/6?

const2013 [10]

Answer:

0.53333...

Step-by-step explanation:

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2 years ago

Read 2 more answers

19. Heather invests $4,900 in an account with a 3.5% interest rate, making no other deposits or withdrawals. What will Heather’s

denis-greek [22]

Answer:

$\$5,828.28$

Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$t=5\ years\\ P=\$4,900\\ r=0.035\\n=2$

substitute in the formula above

$A=\$4,900(1+\frac{0.035}{2})^{2*5}$

$A=\$4,900(1.0175)^{10}=\$5,828.28$

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3 years ago

what information is necessary to prove the triangles congruent by ASA? by AAS ? show your work please.

Zielflug [23.3K]

Answer:

See Explanation

Step-by-step explanation:

For ASA

$\angle R \cong \angle E$

$RQ \cong EF$

$\angle Q \cong \angle F$

$\triangle PRQ \cong \triangle GEF$

For AAS

$\angle P \cong \angle G$

$\angle R \cong \angle E$

$RQ \cong EF$

$\triangle PRQ \cong \triangle GEF$

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3 years ago