Let i = sqrt(-1) which is the conventional notation to set up an imaginary number
The idea is to break up the radicand, aka stuff under the square root, to simplify
sqrt(-8) = sqrt(-1*4*2)
sqrt(-8) = sqrt(-1)*sqrt(4)*sqrt(2)
sqrt(-8) = i*2*sqrt(2)
sqrt(-8) = 2i*sqrt(2)
<h3>Answer is choice A</h3>
Answer:
Kris can make less than 1 batch of cookies
kris can make exactly 1/2 or 1/3 I think
Step-by-step explanation:
<em>OB = 3 cm</em>
- Step-by-step explanation:
<em>AO = radius = 5 cm</em>
<em>AB = 8cm/2 = 4 cm</em>
<em>Pythagora</em>
<em>OB² = AO² - AB²</em>
<em>= (5cm)² - (4cm)²</em>
<em>= 25cm² - 16cm²</em>
<em>= 9 cm²</em>
<em>OB = √9cm²</em>
<em>= 3 cm</em>
Answer:
EY≅ 5.33 cm (nearest to tenth)
Step-by-step explanation:
Two triangles are said to be similar to each other if they have the same shape
(not necessarily the same size) and their corresponding sides are in
proportion
Given that,
AB = 12
DE = 8
BX = 8
ΔABC ∼ ΔDEF means that
- ∠A ∼= ∠D, ∠B ∼=∠E and ∠C ∼= ∠F.
- Further more, their corresponding sides are in proportion.
So,
12/8 = 8/EY
(by doing cross multiplication)
12EY = 8 × 8
12EY = 64
EY = 64 / 12
EY= 5.3333
EY≅ 5.33 cm (nearest to tenth)
