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Trava [24]
3 years ago
9

The kingston review (kr) is testing a new gmat question. the kr wants to determine what proportion of test-takers will answer th

e question correctly, in order to assess its difficulty. in a random sample of 144 test-takers, 75% answered the question correctly. what is the 95% confidence interval for the proportion of test-takers answering the question correctly?
Mathematics
1 answer:
LenKa [72]3 years ago
7 0
[67.9 %, 82.1 %] is the answer when it has 95% confidence interval for the proportion of test-takers who answered the question correctly. So the 95% confidence interval for the proportion of test takers is [67.9 %, 82.1 %] who answered the question correctly, In order to random sample of 144 test-takers and 75% answered question correctly. So the answer in this question is [67.9 %, 82.1 %].
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You would have to calculate the percent first.
Add the total number of students
3420+4680= 8100 students TOTAL

Then you would divide the amount of students by the total

3420 part time/8100 students total = .42 or 42%

4680 full time/8100 total = .58 or 58%

Then you multiply the percentages by 90

(90)(.58)= 52.2

(90)(.42)= 37.8

Rounded

52 full time and 38 part time students
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Goshia [24]
If your ratio is 1 : 50, then for every 1 ft of the model, you have 50 feet of actual church. Thus, if the model is 3.5 ft, then

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