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Komok [63]
3 years ago
13

The table shows transactions from five different bank accounts. Fill in the missing numbers.(IMAGE ATTACHED)

Mathematics
1 answer:
DerKrebs [107]3 years ago
7 0

Answer:

80

64

-175

Step-by-step explanation:

512-432=80

52+12=64

75+-100=-175

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An urn contains n white balls andm black balls. (m and n are both positive numbers.) (a) If two balls are drawn without replacem
Genrish500 [490]

DISCLAIMER: Please let me rename b and w the number of black and white balls, for the sake of readability. You can switch the variable names at any time and the ideas won't change a bit!

<h2>(a)</h2>

Case 1: both balls are white.

At the beginning we have b+w balls. We want to pick a white one, so we have a probability of \frac{w}{b+w} of picking a white one.

If this happens, we're left with w-1 white balls and still b black balls, for a total of b+w-1 balls. So, now, the probability of picking a white ball is

\dfrac{w-1}{b+w-1}

The probability of the two events happening one after the other is the product of the probabilities, so you pick two whites with probability

\dfrac{w}{b+w}\cdot \dfrac{w-1}{b+w-1}=\dfrac{w(w-1)}{(b+w)(b+w-1)}

Case 2: both balls are black

The exact same logic leads to a probability of

\dfrac{b}{b+w}\cdot \dfrac{b-1}{b+w-1}=\dfrac{b(b-1)}{(b+w)(b+w-1)}

These two events are mutually exclusive (we either pick two whites or two blacks!), so the total probability of picking two balls of the same colour is

\dfrac{w(w-1)}{(b+w)(b+w-1)}+\dfrac{b(b-1)}{(b+w)(b+w-1)}=\dfrac{w(w-1)+b(b-1)}{(b+w)(b+w-1)}

<h2>(b)</h2>

Case 1: both balls are white.

In this case, nothing changes between the two picks. So, you have a probability of \frac{w}{b+w} of picking a white ball with the first pick, and the same probability of picking a white ball with the second pick. Similarly, you have a probability \frac{b}{b+w} of picking a black ball with both picks.

This leads to an overall probability of

\left(\dfrac{w}{b+w}\right)^2+\left(\dfrac{b}{b+w}\right)^2 = \dfrac{w^2+b^2}{(b+w)^2}

Of picking two balls of the same colour.

<h2>(c)</h2>

We want to prove that

\dfrac{w^2+b^2}{(b+w)^2}\geq \dfrac{w(w-1)+b(b-1)}{(b+w)(b+w-1)}

Expading all squares and products, this translates to

\dfrac{w^2+b^2}{b^2+2bw+w^2}\geq \dfrac{w^2+b^2-b-w}{b^2+2bw+w^2-b-w}

As you can see, this inequality comes in the form

\dfrac{x}{y}\geq \dfrac{x-k}{y-k}

With x and y greater than k. This inequality is true whenever the numerator is smaller than the denominator:

\dfrac{x}{y}\geq \dfrac{x-k}{y-k} \iff xy-kx \geq xy-ky \iff -kx\geq -ky \iff x\leq y

And this is our case, because in our case we have

  1. x=b^2+w^2
  2. y=b^2+w^2+2bw so, y has an extra piece and it is larger
  3. k=b+w which ensures that k<x (and thus k<y), because b and w are integers, and so b<b^2 and w<w^2

4 0
3 years ago
Josiah invests $360 into an account that accrues 3% interest annually. Assuming no deposits or withdrawals are made, which equat
vlabodo [156]

Answer:

y = 360(1.03)x

Step-by-step explanation:

F = P x (1 + i)^n

F is the future worth, P is the present worth, I will be the interest rate, and n is the number of years. F = ($360)(1.03)^x

The principal amount of the money = $360

Annual rate of interest = 3%

Thus, the amount after x years which is increased by 3%.

Since, this amount represented by y,

The required equation that represents the amount of money in Josiah’s  account, y, after x years is, = 360(1+\frac{3}{100} )^x\\ = 360(1+0.03 )^x\\ = 360(1.03 )^x

This amount represented by y,

Therefore, the required equation that represents the amount of money in Josiah’s account, y, after x years is,

y = 360(1.03 )^x

Hope this helps you!

Have a nice evening! ;)

5 0
3 years ago
Read 2 more answers
Solve for f.<br><br> 8 = 2f + 2
tiny-mole [99]

Answer:

f = 3

Step-by-step explanation:

8 = 2f + 2

-2         -2

6 = 2f

/2    /2

3 = f

5 0
3 years ago
72÷8+3.4-105÷5<br>they say the answer is 0 but don't see how.
Sidana [21]
72/8 +3*4 - 105 /5
= 9 + 12 - 21
= 21 -21
= 0
4 0
2 years ago
In triangle RG shown below. m 63 and m 30 Which of the following is the<br> 63
Tatiana [17]

Answer:

The value of the hypotenuse is 69.77 meters.

Step-by-step explanation:

To determine, in triangle RG, the value of its hypotenuse if its sides measure 63 meters and 30 meters, the following calculation must be performed, applying the Pythagorean theorem:

63 ^ 2 + 30 ^ 2 = X ^ 2

3969 + 900 = X ^ 2

√ 4869 = X

69.77 = X

Therefore, the value of the hypotenuse is 69.77 meters.

7 0
3 years ago
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