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Answer:
0,1,2,3
Explanation:
for the given value of n , l = 0 to n-1
so if n = 4
l = 0 to 4-1
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To solve this, we need the solubility constant for Hg2Cl2,
which is:
Ksp = 1.4 x 10^-18
The ionic formula would be:<span>
</span><span>Hg2Cl2(s) ---> Hg2 2+(aq) + 2Cl-(aq)</span>
<span>
</span>Therefore the total amounts of ions produced = x M Hg2 2+ and 2x M
Cl-
The formula for Ksp in this case is:<span>
</span>Ksp = [Hg2 2+] [Cl-]^2
1.4 x 10^-18 = (x) * (2x)^2
1.4 x 10^-18 = 4x^3 <span>
</span>x = 7.0 x 10^-7 M = [Hg2 2+]
<span>2x = 14 x 10^-7 M = [Cl-]</span>