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Romashka [77]
3 years ago
5

Determine the concentrations of hg22 and cl– in a saturated solution of hg2cl2 in

Chemistry
1 answer:
lutik1710 [3]3 years ago
8 0

To solve this, we need the solubility constant for Hg2Cl2, which is:

Ksp = 1.4 x 10^-18

The ionic formula would be:<span>

</span><span>Hg2Cl2(s)  --->  Hg2 2+(aq) + 2Cl-(aq)</span>

 <span>

</span>Therefore the total amounts of ions produced = x M Hg2 2+ and 2x M Cl- 

 

The formula for Ksp in this case is:<span>

</span>Ksp = [Hg2 2+] [Cl-]^2

1.4 x 10^-18 = (x) * (2x)^2

1.4 x 10^-18 = 4x^3 <span>
</span>x = 7.0 x 10^-7 M = [Hg2 2+]

<span>2x = 14 x 10^-7 M = [Cl-]</span>

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Write the following measurement out of scientific notation. 2.345 x 10^-4 cm.
maw [93]
.0002345 I believe this is correct
7 0
4 years ago
A cube has sides that are 0.03 m . What is the volume of the cube in liters?
Marizza181 [45]

Answer:

0.027 litres

Explanation:

volume of cube = length × base area

volume of cube = 0.03m ×( 0.03m × 0.03m )

volume of cube = 0.03m × ( 0.0009m^2 )

volume of cube = 0.000027m^3

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8 0
3 years ago
2. A block of aluminum with a mass of 140g is cooled from 98.4oC to 62.2oC with a release of 1137J of heat. From these data, cal
NeTakaya
Q =  M * C *ΔT

Q / <span>ΔT  = M

</span>Δf - Δi =  98.4ºC - 62.2ºC = 36.2ºC
<span>
C = 1137 J / 140 * 36.2

C = 1137 / 5068

C = 0.224 J/gºC</span>
8 0
3 years ago
Lipids are soluble in a class of solvents called????
dsp73

Lipids are in a class called fat or lipid solvents.

6 0
4 years ago
Todd drives west to work;54km on way in 1.5hours and then drives home in 2hrs. What is his velocity on the way to work? What is
Nataly [62]

Answer:

Explanation:

Velocity ​​is a physical quantity that expresses the relationship between the space traveled by an object, the time taken for it and its direction. In other words, velocity is associated with the change of position of a body over time.

Its unit in the International System of Units is the meter per second (\frac{m}{s}), but it can also be expressed in \frac{km}{hr}

So, in this case, the speed on the way to work will be:

velocity=\frac{54 km}{1.5 hours}

velocity= 36 \frac{km}{hr}

The velocity on the way back home will be:

velocity=\frac{54 km}{2 hours}

velocity= 27 \frac{km}{hr}

7 0
4 years ago
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