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UkoKoshka [18]
3 years ago
9

A hydrogen-filled balloon was ignited and 1.80 g of hydrogen reacted with 14.4 g of oxygen. How many grams of water vapor were f

ormed?
Chemistry
1 answer:
vesna_86 [32]3 years ago
8 0
Hydrogen reacts with water according to the following equation:
2H2 + O2 ..............> 2H2O

From the periodic table:
molar mass of hydrogen = 1 gram
molar mass of oxygen = 16 grams

Therefore:
4 grams of hydrogen react with 32 grams of oxygen to produce 36 grams of water vapor.

Now, we need to determine the limiting reactant in the equation. By comparing, we can deduce that hydrogen is the limiting reactant (<span>because half of that amount is less than how much O2 you have).
This means that, once the amount of the reacting hydrogen is consumed, the reaction will stop. So, our calculations will be based on the amount of reacting hydrogen.

Now, back to our calculations:
we know that 4 grams of hydrogen are needed to produce 36 grams of water vapor.
To know how many grams of water vapor were produced from 1.8 grams of hydrogen, we will use cross multiplication as follows:
mass of water vapor = (1.8 x 36) / 4 = 16.2 grams</span>
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What is the frequency of a particular type of radiation in hertz given that the wavelength is 4.40 times 10
Reil [10]

Answer:

Frequency=6.81\times 10^{14}\ Hz

Explanation:

The relation between frequency and wavelength is shown below as:

c=frequency\times Wavelength

c is the speed of light having value 2.998\times 10^8\ m/s

Given, Wavelength = 4.40\times 10^{2} nm

Also, 1 m = 10^{-9} nm

So,  

Wavelength = 440\times 10^{-9} m

Thus, Frequency is:

Frequency=\frac{c}{Wavelength}

Frequency=\frac{2.998\times 10^8}{440\times 10^{-9}}\ Hz

Frequency=6.81\times 10^{14}\ Hz

5 0
3 years ago
Pyridine, C5H5N, is a bad-smelling liquid that is a weak base in water. Its pKb is 8.77. What is the pH of a 0.20 M aqueous solu
kari74 [83]

Answer:

pH = 9.26

Explanation:

Let's make the reaction of this weak base:

C₅H₅N  +  H₂O  ⇄    C₅H₅NH⁺  +  OH⁻     Kb

We do not know the Kb, but we can discover it from pKb

Kb = 10^⁻pKb  →  10⁻⁸'⁷⁷ = 1.70×10⁻⁹

So, let's make the expression for Kb

Kb = [OH⁻] . [C₅H₅NH⁺] / [C₅H₅N]

In the equilibrum, we would have  0.20 moles from the begining - x (react)

So we would proudce x moles of OH⁻ and x moles of C₅H₅NH⁺.

In conclussion:

1.70×10⁻⁹ = x . x / (0.20 - x)

To avoid the quadratic formula we can miss the x from the substraction

1.70×10⁻⁹ = x² / 0.20

1.70×10⁻⁹ . 0.20 = x²

We avoid the x from the (0.20-x), because the base is so concentrated, and Kb is very small.

x = √(1.70×10⁻⁹ . 0.20) → 1.84×10⁻⁵

That's the value of [OH⁻], so we can calculate pOH

- log [OH⁻] = pOH → - log 1.84×10⁻⁵ = 4.73

Then pH = 14 - pOH

14 - 4.73 = 9.26

4 0
4 years ago
What are the big differences between physical and chemical properties?
zysi [14]

Explanation:

a physical property happens with the body or something alive while a chemical property has more action with chemicals like H2O and carbon dioxide

4 0
3 years ago
After Rutherford bombarded gold foil with alpha particles, he concluded that the volume of an atom is mostly empty space. Which
vampirchik [111]
<span>Option 4 is the correct answer. Rutherford concluded that the atom's volume was mostly empty space because the stream of alpha particles he directed at the gold foil arived at his detection aparatus mostly intact, indicating that relatively few of the alpha particles had been deflected. This follows because if the atom had not been empty space then the alpha particles would have encountered resistance and gone off course.</span>
5 0
4 years ago
What is the final volume, in milliliters, when 5.80 mL of 25.0 %(m/v) NaOH solution is diluted to give a 3.50 %(m/v) NaOH soluti
Zigmanuir [339]

Answer:

41.43 mL

Explanation:

First we <u>calculate the mass of NaOH in the original solution</u>:

  • 25.0 % m/v means that in 100 mL of solution, there are 25 grams of NaOH.
  • This means that in 5.80 mL, we would have (5.80 * 25/100) <u>1.45 grams of NaOH.</u>

Then we <u>calculate the volume of the diluted solution</u>, using the grams of NaOH (that remain the same throughout the dilution process):

  • 1.45 g NaOH * \frac{100 mL}{3.50gNaOH} = 41.43 mL
7 0
3 years ago
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