A power station with an efficiency e generates W watts of electric power and dissipates D J of heat energy each second to the co
oling water that flows through it. The cooling water increases its temperature by T degrees of Celsius. Find the mass of cooling water which flows through the plant each second. Specific heat capacity of water cw = 4,184 J/kgC e = 0.5 W = 4.2 x 108 watts D = 3.5 x 108 J T = 6 C Enter value in tons (1 ton = 1000 kg). Enter two digits after decimal point.
On adding heat energy to a substance, the temperature would be changed by a particular amount. This relationship between heat energy and temperature is often different for each material. The specific heat, is a value that describes how they relate.
Heat energy = mass flow rate * specific heat * Δ T
