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A stone of mass 5g is projected with a rubber catapult. if the catapult is stretched through a distance of 7cm by an average for
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For the object that has a horizontal velocity component of 6 m/s and a vertical velocity component of 4 m/s we have:
1. The velocity of the object is 7.21 m/s.
2. The angle it makes with the horizontal is 33.7°.
1. The velocity of the object can be found as follows:
Where:
: is the horizontal component of the velocity = 6 m/s
: is the vertical component of the velocity = 4 m/s
Hence, the <u>velocity is</u>:
2. The angle it makes with the <u>horizontal </u>can be calculated with the following trigonometric function:
Where:
θ: is the angle it makes with the horizontal
Therefore, the <u>angle is</u>:
You can learn more about the components of the velocity here: brainly.com/question/2285233?referrer=searchResults
I hope it helps you!
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