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Sladkaya [172]
2 years ago
7

A stone of mass 5g is projected with a rubber catapult. if the catapult is stretched through a distance of 7cm by an average for

ce of 70 North, calculate the instantaneous velocity of the stone when released ​
Physics
1 answer:
weqwewe [10]2 years ago
4 0

Explanation:

solution: mass m = 5g = 0.005kg; extension e = 7cm = 0.07m; force f = 70 N; velocity = ?; using: work done in elastic material w = 1/2 fe = 1/2 ke2 = 1/2 mv2 - the kinetic energy of the moving stone. 1/2 fe =...

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w = angular speed of the meter stick as it hits the floor

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For a stick, momentof inertia about one end has the formula as

I = \frac{mL^{2} }{3}

Using conservation of energy

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