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3 years ago

33=-3 (3-2)solve the equation please I need help

Mathematics

1 answer:

hammer [34]3 years ago

6 0

Where is the variable?

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Identify whether each cube root or square root lies between 2 and 3, 4 and 5, or 9 and 10.

leva [86]

Answer:

The cube root and square root are not given, but I'm going to give a chart that might help.

Square roots:

2 = √4

3 = √9

4 = √16

5 = √25

9 = √81

10 = √100

Cube roots:

2 = ^3√8

3 = ^3√27

4 = ^3√64

5 = ^3√125

9 = ^3√729

10 = ^3√1000

3 0

3 years ago

Solve each equation in the interval from 0 to 2pi. Round your answer to the nearest hundredth.

kirill115 [55]

I think the answer is b. cos(pi theta)= -0.6

6 0

4 years ago

Angles BAE and FAC are straight angles. What angle relationship best describes angles BAC and EAF?Adjacent anglesComplementary a

Natalka [10]

The best angle relationship that describes angles BAC and EAF is supplementary angles

The sum of angle on a straight line is supplementary i.e. they sum up to 180 degrees.

If Angles BAE and FAC are straight angles, it means they are linear pairs and their sum is 180 degrees. Mathematically;

m<BAE + m<FAC = 180degrees

Hence we can conclude that the best angle relationship that describes angles BAC and EAF is supplementary angles

Learn more here: brainly.com/question/22309882

8 0

3 years ago

In a triangle, Angle B is twice as large as Angle A. Angle C is five more than

Leona [35]

Answer:

<A = 35 degrees

Step-by-step explanation:

<A = x

<B = 2x

<C = 2x + 5

X + 2x + 2x + 5 = 180 degrees

5x + 5 = 180

5x = 180 -5

x = 175/5

x = 35

4 0

3 years ago

Please help!! thank you.

Zina [86]

(A) Product of $-2x^{3}+x-5$ and $x^{3}-3x-4$ is:

$(-2x^{3}+x-5)(x^{3}-3x-4)$

$=-2x^{3}(x^{3}-3x-4)+x(x^{3}-3x-4)-5(x^{3}-3x-4)$

$=(-2x^{3})(x^{3})+(-2x^{3})(-3x)+(-2x^{3})(-4)+x(x^{3})+(x)(-3x)+(x)(-4)+(-5)(x^{3})+(-5)(-3x)+(-5)(-4)$

$=-2x^{6}+6x^{4}+8x^{3}+x^{4}-3x^{2}-4x-5x^{3}+15x+20$

$=-2x^{6}+6x^{4}+x^{4}+ 8x^{3}-5x^{3}-3x^{2}-4x+15x+20$

$=-2x^{6}+7x^{4}+3x^{3}-3x^{2}+11x+20$

(B) Yes.

Product of $-2x^{3}+x-5$ and $x^{3}-3x-4$ = Product of $x^{3}-3x-4$ and $-2x^{3}+x-5$ because multiplication is commutative.

Commutative Property of multiplication says that a.b = b.a.

Thus, multiplication is same irrespective of the order of two numbers.

5 0

4 years ago