All categories

3 years ago

Use the change of base formula to compute log5 9.

1 answer:

5 0

Let log₅9 = x
Then
5ˣ = 9

Take log to base 10 of both sides.
log₁₀5ˣ = log₁₀9
x log₁₀5 = log₁₀9

Therefore
log₅9 = log₁₀9/log₁₀5
= 0.9542/0.699
= 1.3652

Answer: 1.365 (nearest thousandth)

You might be interested in

18. Solve the quadratic equation by using the graph. Look at screenshot

Rasek [7]

Step-by-step explanation:

As seen from the graph, the curve crosses the x-axis when x = -1 and x = 1. The y-intercept of the curve is -1.

Hence, the quadratic equation of the curve is y = x^2 - 1.

3 0

3 years ago

اريد الحل بليززززززز٥س_٣= ٣٧

trapecia [35]

Wallahi my guy init

7 0

3 years ago

Find the 6th term of the arithmetic sequence X – 9, -X – 11, -3.3 – 13, ...

MrMuchimi

Answer:

$-13x-23$

Step-by-step explanation:

Given sequence: $x-9, -x-11, -3x-13$

Therefore,

$a_1=x-9$
$a_2=-x-11$
$a_3=-3x-13$

General form of an arithmetic sequence: $a_n=a+(n-1)d$

(where a is the first term and d is the common difference)

To find the common difference, subtract a term from the next term:

$\begin{aligned}d & =a_2-a_1\\ & =(-x-11)-(x-9)\\ & = -x-11-x+9\\ & = -2x-2\end{aligned}$

Therefore,

$a_n & =(x-9)+(n-1)(-2x-2)$

To find the 6th term, input n = 6 into the equation:

$\begin{aligned}\implies a_6 & =(x-9)+(6-1)(-2x-2)\\ & = (x-9)+7(-2x-2)\\ & = x-9-14x-14\\ & = -13x-23\end{aligned}$

3 0

2 years ago

River C is 300 Miles Longer than River D. If the sum of their lengths is 5,570 miles, what is the length of each river?

d1i1m1o1n [39]

$x-\ length\ of\ river\ D\\
x+300-\ length\ of\ river\ C\\\\
5570=x+x+300\\
5570=2x+300\ \ \ | subtract\ 300\\5270=2x\ \ \ | divide\ by\ 2\\x=2635\\\\
River\ C\ is\ 2935miles\ long\ and\ river\ D\ 2635\ miles\ long.$

6 0

3 years ago

Given that f(x) = 2x – 1, find f(6). Your answer: 6 7 11 13

Kruka [31]

Answer:

Step-by-step explanation:

2 times 6 is 12 minus 1 is 11

4 0

3 years ago

Read 2 more answers