Question

Please help!!!!!!!!!!

Answer 1

$f(x)=2x^2-4x+1$

Substitute the values of x to the equation of the function f:

$x=-1\to f(-1)=2(-1)^2-4(-1)+1=2(1)+4+1=7\\\\x=2\to f(2)=2(2^2)-4(2)+1=2(4)-8+1=1$

Therefore we have two points (-1, 7) and (2, 1).

We can calculate the slope of line l.

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

Substitute:

$m=\dfrac{1-7}{2-(-1)}=\dfrac{-6}{3}=-2$

Answer: A) -2.