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Natalka [10]
4 years ago
15

Determine the vertical asymptote for the rational function f of x equals quantity x minus 4 end quantity divided by quantity 2 t

imes x minus 3 end quantity.
Mathematics
2 answers:
Leto [7]4 years ago
8 0

Answer:

Step-by-step explanation:

The vertical asymptote exists where the denominator of that function equals 0.  To find where it equals 0, set the denominator equal to 0 and solve for x:

2x - 3 = 0 and

2x = 3 so

x = 3/2

The vertical asymptote is at x = 3/2 or 1.5

dmitriy555 [2]4 years ago
6 0

Answer:

The answer is 3/2.

Step-by-step explanation:

The rational function is below:

f(x)=(x-4)/(2x-3)

To determine of the vertical asymptote of the rational function we need to find the x value that makes denominator zero.

Then;

2x-3=0

x=3/2

the vertical asymptote for the rational function is 3/2

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7 0
4 years ago
What is the logarithmic function modeled by the following table? x f(x) 9 2 27 3 81 4
Nataly_w [17]

Answer:

Required logarithmic function is :

f\left(x\right)=\log_3\left(x\right)

Step-by-step explanation:

We have been fiven that table for the logarithmic function is:

x f(x)

9 2

27 3

81 4

which can be rewritten as:

x f(x)

3^2 2

3^3 3

3^4 4

Which are basically powers of 3

So we can use logarithmic function as

\log_3\left(9\right)=\log_3\left(3^2\right)=2\log_3\left(3\right)=2(1)=2

Hence required logarithmic function is :

f\left(x\right)=\log_3\left(x\right)

8 0
3 years ago
F(x) = 2x-1<br> What is f(13)?
Delicious77 [7]

Answer:

f(13)=2x-1, x=7

Step-by-step explanation:

7*2=14, 14-1=13

vise versa

f(13)=2(7)-1

4 0
4 years ago
Read 2 more answers
Two ratios by entering less than greater than or equal than 16 to 15, 30 to 80
Mumz [18]

Answer:

6:15>30:80

Step-by-step explanation:

The ratio;

6:15 written in the form x/1 is equivalent to 2/5 or 0.4

30:80 written in the form x/1 is equal to 3/8 or 0.375

0.4 is greater than 0.375

Therefore;

<u>6:15>30:80</u>

6 0
3 years ago
A 1200 gram sample of radioactive matter will completely decay (be undetectable) in 10 hours. There exists a set of ordered pair
julia-pushkina [17]

Using it's concept, the range of the function is given as follows:

0 ≤ m ≤ 1200.

<h3>What is the range of a function?</h3>

The range of a function is the set that contains all possible output values for the function.

For this problem, we have to consider these two bullet points next, considering the mass is the output value of the function.

  • The smallest possible mass for the substance is of 0 grams, as after the substance decays to 0 grams, it will not assume a negative value, it will just disappear.
  • The greatest possible mass for the substance is the initial mass of 1200 grams, as the substance does not adquire mass with time, it just loses it.

Considering these masses, the range of the function is given as follows:

0 ≤ m ≤ 1200.

More can be learned about the range of a function at brainly.com/question/10197594

#SPJ1

3 0
1 year ago
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