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Darya [45]
3 years ago
12

A 0.3 ml dose of a drug is injected into a patient steadily for 0.65 seconds. At the end of this time, the quantity, , of the dr

ug in the body starts to decay exponentially at a continuous rate of 0.35 percent per second. Using formulas, express as a continuous function of time, , in seconds.
Mathematics
1 answer:
Darya [45]3 years ago
4 0
Use the compound interest formula: A=P(1+i)^t.

P is the initial amount of the drug, 0.3ml.
i is - 0.0035.
t is in seconds.

You'll get:
A=0.3(1-0.0035)^t.

Sub in any value on t to find out how many ml are left t seconds after injection.

The 0.65 second injection time does not seem to be relevant as the question clearly states that the exponential decay starts AFTER the injection is completed.
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Help! Please do a,b,c and d with explanation
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  c. 105 km

  d. 193 km

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a. The bearing of E from A is given as 55°. The bearing in the opposite direction, from E to A, is this angle with 180° added:

  bearing of A from E = 55° +180° = 235°

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b. The internal angle at E is the difference between the external angle at C and the internal angle at A:

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The law of sines tells you ...

  CE/sin(∠A) = CA/sin(∠E)

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c. The internal angle at C is the supplement of the external angle, so is ...

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The distance PE is opposite that angle, and CE is the hypotenuse of the right triangle CPE. The sine trig relation is helpful here:

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  sin(46°) = PE/CE

  PE = CE·sin(46°) = 146.03 km·sin(46°) ≈ 105.05 km

  PE ≈ 105 km

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d. DE can be found from the law of cosines:

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  DE² = 60² +146.03² -2(60)(146.03)cos(134°) ≈ 37099.43

  DE = √37099.43 ≈ 192.6 . . . km

  DE is about 193 km

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2 years ago
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