14. 36x^2 - 16
4(9x^2 - 4) =
4(3x + 2)(3x - 2) <==
15. 3x^2 + 10x - 8
(3x - 2)(x + 4) <==
16. 5x^2 - 16x + 15 = 4x - 5
5x^2 - 16x - 4x + 15 + 5 = 0
5x^2 - 20x + 20 = 0
5(x^2 - 4x + 4)
5(x - 2)(x - 2)
x - 2 = 0....x = 2
The answer is 2x-4
Factor out 5 from the expression and then reduce the numbers with the greatest common factor 5
<span>To convert a fraction to decimal simply divide the top number by the bottom number. This would give you 1.4. Hope this helped!</span>
Answer:
10 and -3
Step-by-step explanation:
10 x -3 = -30
10 + (-3) = 7
I'm assuming that you meant:
1
f(x) = -------- and that you want to find the value of x at which f(x) = h(x).
x+1
Of course you could create a table for each f(x) and h(x), but setting f(x)=h(x) and solving for x algebraically would be faster and more efficient:
1
f(x) = -------- = 2x + 3 = h(x). Then 1 = (x+1)(2x+3) = 2x^2 + 3x + 2x + 3
x+1
or 1 = 2x^2 + 5x + 3, or 2x^2 + 5x + 2 = 0.
This is a quadratic equation with a=2, b=5 and c=2. The discriminant is b^2-4ac, or 5^2-4(2)(2), OR 25-16= 9.
Thus, the roots are
-5 plus or minus sqrt(9)
x = ------------------------------------
2(2)
-5 plus or minus 3
= ----------------------------------
4
= {-1/2, -2}
Thus, f(x) = h(x) at both x=-1/2 and x= -2.
