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victus00 [196]
4 years ago
5

Roberta is thinking about joining the food co-op store. If she pays $10.00 to join, she will get 10% off on all the groceries sh

e buys there.How much must she buy before her savings equal her membership fee?
Mathematics
1 answer:
IceJOKER [234]4 years ago
8 0

$100 worth of groceries.

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How much would 55 pounds on mercury weight on earth
azamat
144.74 pounds, I rounded the answer. to get this you would divide 55 by .38 .
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I need help answering this question thank you
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3 years ago
Four square pieces of corkboard are lined up to make a rectangle. The area of the entire corkboard is
Pavel [41]

9514 1404 393

Answer:

  a) attached

  b) 100 square inches, 1/4 of the total

  c) square root of area

  d) multiply by 4

Step-by-step explanation:

a) A diagram is attached

__

b) If the total area consists of 4 squares of the same size, then the area of one square will be 1/4 of the total area. 1/4 of 400 square inches is 100 square inches, the area of one square.

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c) The area of a square is the square of the side length. You find the side length by finding the square root of the area. √(100 in²) = 10 in, the side length of each square.

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d) The rectangle is 4 squares laid side by side, so its length is 4 times the side length of one square: 4×10 in = 40 in.

4 0
3 years ago
Fill in the blanks with the correct symbol to make each statement true. Use +,-, x, divide or parentheses to obtain the given so
Stolb23 [73]

Answer:

4×4÷4+4=4

(4×4+4)÷4=5

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5 0
4 years ago
The molar mass of AlCl3 is 133.34 g/mol. How many molecules of AlCl3 are there in 2 g?
Mnenie [13.5K]

To solve this problem, we have to apply mole-concept to this and we would need the molar mass of AlCl3.  2g of AlCl3 contains 9.034*10^21 molecules.

<h3>Number of Molecules in 2g of AlCl3</h3>

The molar mass of AlCl3 is given as 133.34g/mol

Data;

  • mass = 2g
  • molar mass = 133.34g/mol

Using the mole concept, we can equate the molar mass to the number of molecules present in the entity.

133.34g = 6.023*10^2^3

If we equate this

133.34g = 6.023*10^2^3\\2g = x molecules\\x = \frac{2*6.023*10^2^3}{133.34} \\x = 9.034*10^2^1 molecules

From the calculations above, 2g of AlCl3 contains 9.034*10^21 molecules.

Learn more on mole concept here;

brainly.com/question/21150359

#SPJ1

5 0
2 years ago
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