With an isotropic source, you can think on the radiation like a expanding sphere, where you will measure the same cps in any point while you keep the same distance to the source, ence the radius of the sphere remains constant. So, you know that the relation depends on the radius, also, when the sphere grows, the radiation in it expands in more surface, ence the density of particles will decrease, particularly, like 
then, in 15cm you will have 55cps = A/(10*10) where A is the "intensity of the source" whit this you can know the value of A = 55cps*100
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then, for 22cm, Y = 55cps*100/(22*22) = 20.66 cps.
Answer:
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Step-by-step explanation:
Answer:
If there is a variable term and a constant on each side of the equation, then you will need to use the addition or subtraction property of equality once to isolate the variable term and once to isolate the constant.
The area of the rectangle is 128 ft. the area of the triangle is 12ft. together, it’s 140 ft.