
Taking the square root of both sides gives two possible cases,

or

Recall that

If
and
, we have

so in the equations above, we can write

Then in the first case,


(where
is any integer)


and in the second,




Then the solutions that fall in the interval
are

Solution-
First 9 letters of alphabet are- A,B,C,D,E,F,G,H,I
Total number of ways of selection of 4 letters from 9 alphabets = 9C4
=9!÷((4!).(9-4)!) = 9!÷(4!×5!) = (9×8×7×6)÷(24) = 126
The number of ways of arranging these 4 numbers = 4! = 24
∴ Total number of possible permutations = 9C4×4! = 126×24 = 3024
∴ option number 2 is correct.
Answer:
I don't know but if you figure it out tell me. Thanks
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
I did the math! and got 15
Hope this helps!
Answer:
76/100 or simplified into 19/25