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Phantasy [73]
4 years ago
9

Compounds mixtures and elements ​

Chemistry
1 answer:
Jlenok [28]4 years ago
8 0

Compound - made out of two or more types of elements chemically combined

Mixture - two or more substances in which the substances retain their identity

Element - simplest form of matter that is present by itself

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Write skeleton equations for these reactions. a. butane(l) + oxygen (g) --> carbon dioxide(g) + water(l).
mylen [45]
Skeleton equation is actually a chemical reaction whee the reactants and products are written in their chemical formula. In this problem, this is actually a combustion reaction of butane. The chemical formula for butane is C₄H₁₀.

<em>C₄H₁₀ (l) + 6.5 O₂ (g) --> 4 CO₂ (g) + 5 H₂O (l)</em>
4 0
3 years ago
What is molarity ? also write its formula ?​
Tpy6a [65]
Number of moles of solute in 1L of solution is called molarity.

Molarity=number of moles of solute/volume in L.
i hope this helps u....ny doubts are welcome
4 0
3 years ago
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Which change would most likely increase the resistance in the circuit ?
yaroslaw [1]

Answer:

I think it would be C but don't quote me on it

Explanation:

It adds another obstacle for the current to go through

4 0
2 years ago
1. How much heat is required to raise the temperature of 4.64kg of lead from 150°C to 219°C?
diamong [38]

Answer: An amount of 40980.48 J/g^{o}C heat is required to raise the temperature of 4.64kg of lead from 150°C to 219°C.

Explanation:

Given: mass of lead = 4.64 kg

Convert kg into grams as follows.

1 kg = 1000 g\\4.64 kg = 4.64 kg \times \frac{1000 g}{1 kg}\\= 4640 g

T_{1} = 150^{o}C

T_{2} = 219^{o}C

The standard value of specific heat of lead is 0.128 J/g^{o}C.

Formula used to calculate heat is as follows.

q = m \times C \times \Delta T

where,

q = heat energy

m = mass of substance

C = specific heat of substance

\Delta T = change in temperature

Substitute the value into above formula as follows.

q = m \times C \times \Delta T\\= 4640 g \times 0.128 J/g^{o}C \times (219 - 150)^{o}C\\= 40980.48 J/g^{o}C

Thus, we can conclude that 40980.48 J/g^{o}C heat is required to raise the temperature of 4.64kg of lead from 150°C to 219°C.

8 0
3 years ago
The following properties are either physical or chemical. Which one is different from the rest based on those two categories?
Nadusha1986 [10]

Answer:

Boiling point: physical

Density: physical

Ductility: physical

Heat of combustion: chemical

Explanation:

Chemical properties can only be analyzed by putting the substance through a chemical reaction, such as combustion.

Physical properties can be analyzed without altering the substance chemically. With that in mind:

4 0
4 years ago
Read 2 more answers
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